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Area of a triangle · 3 marks

The area of a right-angled triangle is 54 sq. cm. One of its legs has length 12 cm. Find its perimeter.

Answer: 12 × 12 × x = 54 ⇒ x = 9 cm; hypotenuse = √(144 + 81) = 15 cm. Perimeter = 12 + 9 + 15 = 36 cm.

Step-by-step solution

Given: Area 54 cm2; One leg 12 cm
To find: Perimeter

Idea: In a right-angled triangle the two legs are a base and a height, so the area gives the other leg; then use the Baudhāyana–Pythagoras theorem.

  1. 12 × 12 × x = 54 ⇒ 6x = 54 ⇒ x = 9 cm (other leg).1 mark
  2. Hypotenuse = √(122 + 92) = √(144 + 81) = √225 = 15 cm.1 mark
  3. Perimeter = 12 + 9 + 15 = 36 cm.1 mark
The perimeter is 36 cm.

Answer to write in the exam

12 × 12 × x = 54 ⇒ x = 9 cm

Hypotenuse = √(122 + 92) = √225 = 15 cm

Perimeter = 12 + 9 + 15

∴ Perimeter = 36 cm

Common mistakes that cost marks

  • Taking 12 cm as the hypotenuse. It is a leg (the question says so).
  • Stopping at 9 cm and not adding the hypotenuse.

How this can come in the exam

MCQ (1 mark)

A right-angled triangle has area 30 cm2 and one leg 5 cm. Its hypotenuse is

  1. 12 cm
  2. 15 cm
  3. 17 cm
  4. 13 cm
Show answer

(D) 13 cm
Other leg = 12; hypotenuse = √(25 + 144) = 13 cm.

Try one yourself

A right-angled triangle has area 84 cm2 and one leg 24 cm. Find its perimeter.

Show answer

Other leg 7, hypotenuse 25, perimeter 56 cm.

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