The area of a right-angled triangle is 54 sq. cm. One of its legs has length 12 cm. Find its perimeter.
Answer: 12 × 12 × x = 54 ⇒ x = 9 cm; hypotenuse = √(144 + 81) = 15 cm. Perimeter = 12 + 9 + 15 = 36 cm.
Step-by-step solution
Given: Area 54 cm2; One leg 12 cm
To find: Perimeter
To find: Perimeter
Idea: In a right-angled triangle the two legs are a base and a height, so the area gives the other leg; then use the Baudhāyana–Pythagoras theorem.
- 12 × 12 × x = 54 ⇒ 6x = 54 ⇒ x = 9 cm (other leg).1 mark
- Hypotenuse = √(122 + 92) = √(144 + 81) = √225 = 15 cm.1 mark
- Perimeter = 12 + 9 + 15 = 36 cm.1 mark
The perimeter is 36 cm.
Answer to write in the exam
12 × 12 × x = 54 ⇒ x = 9 cm
Hypotenuse = √(122 + 92) = √225 = 15 cm
Perimeter = 12 + 9 + 15
∴ Perimeter = 36 cm
Common mistakes that cost marks
- Taking 12 cm as the hypotenuse. It is a leg (the question says so).
- Stopping at 9 cm and not adding the hypotenuse.
How this can come in the exam
MCQ (1 mark)
A right-angled triangle has area 30 cm2 and one leg 5 cm. Its hypotenuse is
- 12 cm
- 15 cm
- 17 cm
- 13 cm
Show answer
(D) 13 cm
Other leg = 12; hypotenuse = √(25 + 144) = 13 cm.
Try one yourself
A right-angled triangle has area 84 cm2 and one leg 24 cm. Find its perimeter.
Show answer
Other leg 7, hypotenuse 25, perimeter 56 cm.
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