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Area of a triangle · 3 marks

An isosceles triangle has base 10 cm, and its area is 60 cm2. What are the lengths of the equal sides?

Answer: 12 × 10 × h = 60 ⇒ h = 12 cm. Equal side = √(52 + 122) = 13 cm.

Step-by-step solution

Given: Base 10 cm; Area 60 cm2
To find: Length of each equal side

Idea: The area gives the height; the height and half the base are the legs of a right triangle whose hypotenuse is the equal side.

  1. 12 × 10 × h = 60 ⇒ 5h = 60 ⇒ h = 12 cm.1 mark
  2. The height bisects the base, so half the base = 5 cm.½ mark
  3. Equal side = √(52 + 122) = √169 = 13 cm.1½ marks
Each of the equal sides is 13 cm.

Check: Heron with 13, 13, 10: s = 18, √(18 × 5 × 5 × 8) = √3600 = 60 ✓.

Answer to write in the exam

12 × 10 × h = 60 ⇒ h = 12 cm

Half base = 5 cm

Equal side = √(52 + 122) = √169

∴ Equal sides = 13 cm each

Common mistakes that cost marks

  • Using the full base 10 with the height: √(100 + 144) ≈ 15.6 (wrong).
  • Forgetting the 12 and getting h = 6.

How this can come in the exam

MCQ (1 mark)

An isosceles triangle has base 16 cm and area 48 cm2. Each equal side is

  1. 6 cm
  2. 8 cm
  3. 10 cm
  4. 12 cm
Show answer

(C) 10 cm
h = 6; side = √(82 + 62) = 10 cm.

Try one yourself

An isosceles triangle has base 30 cm and area 300 cm2. Find its equal sides.

Show answer

h = 20; side = √(152 + 202) = 25 cm.

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