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Heron’s formula · 3 marks

The sides of a triangle are in the ratio 2: 3: 4, and its perimeter is 45 cm. Find its area.

Answer: Sides 10, 15, 20 cm; s = 22.5. Area = √(22.5 × 12.5 × 7.5 × 2.5) = 75√154 ≈ 72.62 cm2.

Step-by-step solution

Given: Ratio 2 : 3 : 4; Perimeter 45 cm
To find: Area

Idea: Find the sides from the ratio, then use Heron’s formula. Working with halves (452, 252 …) keeps the square root exact.

  1. 2x + 3x + 4x = 45 ⇒ x = 5. Sides: 10, 15, 20 cm. s = 22.5 cm.1 mark
  2. s − a = 12.5, s − b = 7.5, s − c = 2.5. Area = √(452 × 252 × 152 × 52) = √843754.1 mark
  3. 84375 = 5625 × 15 = 752 × 15, so area = 75√154 ≈ 72.62 cm2.1 mark
Area = (75√15)/4 cm² ≈ 72.62 cm².

Check: 22.5 × 12.5 × 7.5 × 2.5 = 5273.4…, and 72.622 ≈ 5273.6 ✓.

Answer to write in the exam

9x = 45 ⇒ x = 5; sides 10, 15, 20 cm

s = 22.5 cm

Area = √(22.5 × 12.5 × 7.5 × 2.5) = √843754

= 75√154

∴ Area ≈ 72.62 cm2

Common mistakes that cost marks

  • Taking x = 45 ÷ 3 = 15.
  • Rounding the factors early (e.g. 22.5 → 23), which changes the answer noticeably.

How this can come in the exam

MCQ (1 mark)

The sides of a triangle are in the ratio 3 : 4 : 5 and its perimeter is 36 cm. Its area is

  1. 54 cm2
  2. 48 cm2
  3. 60 cm2
  4. 72 cm2
Show answer

(A) 54 cm2
Sides 9, 12, 15 (right-angled): 12 × 9 × 12 = 54 cm2.

Try one yourself

The sides of a triangle are in the ratio 7 : 15 : 20 and its perimeter is 126 cm. Find its area.

Show answer

Sides 21, 45, 60; s = 63; √(63 × 42 × 18 × 3) = √142884 = 378 cm2.

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