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Sample space and events · 2 marks

A child has 2 shirts (one red and one blue) and 3 types of pants (jeans, khakis, and shorts). List all the possible combinations of outfits consisting of one shirt and one pair of pants. Display your answer in a table format.

Answer: 2 × 3 = 6 outfits: (Red, Jeans), (Red, Khakis), (Red, Shorts), (Blue, Jeans), (Blue, Khakis), (Blue, Shorts).

Step-by-step solution

Given: Shirts: red, blue; Pants: jeans, khakis, shorts

Idea: Put the shirts down the side and the pants across the top. Each box of the table is one outfit, so the table shows every combination exactly once.

  1. Each of the 2 shirts can be worn with each of the 3 pants: 2 × 3 = 6 combinations.½ mark
  2. Shirt ↓ / Pants →JeansKhakisShorts
    RedRed shirt, jeansRed shirt, khakisRed shirt, shorts
    BlueBlue shirt, jeansBlue shirt, khakisBlue shirt, shorts
    1 mark
  3. So there are 6 possible outfits. As a sample space: S = {(Red, Jeans), (Red, Khakis), (Red, Shorts), (Blue, Jeans), (Blue, Khakis), (Blue, Shorts)}.½ mark
6 outfits: red shirt with jeans, khakis or shorts; blue shirt with jeans, khakis or shorts (2 × 3 = 6), shown in a 2-row, 3-column table.

Check: Each row of the table has 3 outfits and there are 2 rows: 6 ✓. No outfit appears twice.

Answer to write in the exam

Number of outfits = 2 × 3 = 6

Table (rows: shirt; columns: pants):

Red: (Red, Jeans) | (Red, Khakis) | (Red, Shorts)

Blue: (Blue, Jeans) | (Blue, Khakis) | (Blue, Shorts)

∴ S = {(Red, Jeans), (Red, Khakis), (Red, Shorts), (Blue, Jeans), (Blue, Khakis), (Blue, Shorts)}; 6 outfits

Common mistakes that cost marks

  • Adding instead of multiplying: 2 + 3 = 5 outfits. Each shirt goes with every pair of pants, so it is 2 × 3.
  • Listing the 5 clothes as the answer. An outfit is a pair (one shirt and one pair of pants).
  • Giving a list when the question asks for a table. Draw the table with shirts as rows and pants as columns.

How this can come in the exam

MCQ (1 mark)

A school uniform comes in 3 shirt colours and some trouser colours, giving 12 different shirt-and-trouser combinations. The number of trouser colours is

  1. 4
  2. 9
  3. 15
  4. 36
Show answer

(A) 4
3 × (number of trouser colours) = 12, so 12 ÷ 3 = 4.

Short answer (2 marks)

A child chooses a cap (white or black) and a pair of shoes (sports or sandals). Show all the outfits in a table. If one outfit is chosen at random, find the probability that it has a white cap and sandals.

Show answerTable: White–Sports, White–Sandals, Black–Sports, Black–Sandals (2 × 2 = 4 outfits). Only (White, Sandals) is favourable: P = 14.

Try one yourself

A child has 3 T-shirts (white, yellow, green) and 2 pairs of shorts (black, grey). How many outfits are possible? List them.

Show answer

3 × 2 = 6: (White, Black), (White, Grey), (Yellow, Black), (Yellow, Grey), (Green, Black), (Green, Grey).

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