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Impossible and certain events · 2 marks

I throw a pair of 6-sided dice. Write down an event that has a probability of 0 and an outcome that has a probability of 1.

Answer: Probability 0: “the sum of the two numbers is 13” (impossible; the largest sum is 12). Probability 1: “the sum of the two numbers is between 2 and 12” (certain; it always is).

Step-by-step solution

Given: Two 6-sided dice: 6 × 6 = 36 equally likely outcomes, from (1, 1) to (6, 6)

Idea: An impossible event has no favourable outcomes (P = 036 = 0). A certain event contains every outcome in the sample space (P = 3636 = 1). No single pair of numbers is certain (each has probability 136), so the probability-1 answer has to be an event that includes all 36 outcomes.

  1. The sum of two dice is at least 1 + 1 = 2 and at most 6 + 6 = 12.½ mark
  2. Probability 0: “The sum is 13.” No outcome gives 13, so the number of favourable outcomes is 0 and P = 036 = 0. (Other answers: “the sum is 1”, “a die shows 7”.)½ mark
  3. Probability 1: “The sum is between 2 and 12 (inclusive).” All 36 outcomes give such a sum, so P = 3636 = 1. (Other answers: “each die shows a number less than 7”, “the sum is less than 13”.)½ mark
  4. Note: a single outcome such as (3, 4) has probability 136, not 1. So the “outcome” with probability 1 must be an event made of all 36 outcomes, i.e. the whole sample space.½ mark
Probability 0: ‘the sum of the numbers is 13’ (impossible). Probability 1: ‘the sum of the numbers is between 2 and 12’ (certain), which includes all 36 outcomes.

Check: Count: no pair adds to 13, and every one of the 36 pairs adds to a number from 2 to 12 ✓.

Answer to write in the exam

n(S) = 6 × 6 = 36; possible sums 2 to 12

Event A: sum = 13; n(A) = 0; P(A) = 036 = 0

Event B: sum between 2 and 12; n(B) = 36; P(B) = 3636 = 1

∴ Probability 0: the sum is 13. Probability 1: the sum is between 2 and 12.

Common mistakes that cost marks

  • Giving “getting a double six” as the probability-0 event. It is possible (probability 136).
  • Giving one particular pair such as (6, 6) as the probability-1 outcome. Any single pair has probability 136; only an event covering all outcomes is certain.
  • Giving “the sum is 12” as impossible. 6 + 6 = 12 can happen.

How this can come in the exam

MCQ (1 mark)

Two dice are thrown together. The probability that the product of the two numbers is 0 is

  1. 0
  2. 136
  3. 16
  4. 1
Show answer

(A) 0
Neither die shows 0, so the product is never 0: impossible, probability 0.

Assertion–Reason (1 mark)

Assertion (A): When two dice are thrown, the probability that the sum is less than 13 is 1.
Reason (R): The probability of an event that includes every outcome of the sample space is 1.

  1. Both A and R are true, and R is the correct explanation of A.
  2. Both A and R are true, but R is not the correct explanation of A.
  3. A is true but R is false.
  4. A is false but R is true.
Show answer

(A) Both A and R are true, and R is the correct explanation of A.
Every sum is at most 12, so the event includes all 36 outcomes; R is exactly why A is true.

Try one yourself

A single die is thrown. Write an event with probability 0 and an event with probability 1.

Show answer

Probability 0: getting 8 (or getting 0). Probability 1: getting a number from 1 to 6 (or a number less than 7).

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