If the length of a rectangle is three more than twice its width and its perimeter is 24 cm, what are the dimensions of the rectangle?
Step-by-step solution
To find: The length and the width
Idea: “Three more than twice the width” means 2w + 3. Perimeter of a rectangle = 2(length + width).
- Let the width be w cm. Then the length is (2w + 3) cm.½ mark
- Perimeter: 2[(2w + 3) + w] = 24, so 2(3w + 3) = 24.1 mark
- 3w + 3 = 12, so 3w = 9 and w = 3.1 mark
- Width = 3 cm; length = 2 × 3 + 3 = 9 cm.½ mark
Check: 2(9 + 3) = 24 ✓ and 9 = 2 × 3 + 3 ✓.
Answer to write in the exam
Let width = w cm; length = (2w + 3) cm
2[(2w + 3) + w] = 24
3w + 3 = 12 ⇒ 3w = 9 ⇒ w = 3
Length = 2(3) + 3 = 9
∴ Length = 9 cm, width = 3 cm
Common mistakes that cost marks
- Writing the length as 3(2w) or 2(w + 3). “Three more than twice the width” is 2w + 3.
- Using perimeter = length + width = 24. The perimeter has two lengths and two widths.
- Giving only w = 3 and forgetting to find the length.
How this can come in the exam
The length of a rectangle is 4 cm more than its width and its perimeter is 40 cm. Its width is
- 8 cm
- 12 cm
- 18 cm
- 9 cm
Show answer
(A) 8 cm
2(w + 4 + w) = 40, so 2w + 4 = 20 and w = 8 cm.
The length of a rectangular field is 5 m less than three times its width. The perimeter is 150 m. Find the dimensions.
Show answer
Length = 3w − 5 (½ mark). 2(3w − 5 + w) = 150, so 4w − 5 = 75 (1 mark). w = 20 m (1 mark), length = 55 m (½ mark).Try one yourself
The length of a rectangle is one more than three times its width, and its perimeter is 42 cm. Find its dimensions.
Show answer
2(3w + 1 + w) = 42, so 4w + 1 = 21 and w = 5. Width 5 cm, length 16 cm.
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