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Linear equations · 3 marks

If the length of a rectangle is three more than twice its width and its perimeter is 24 cm, what are the dimensions of the rectangle?

Answer: Width = 3 cm, length = 9 cm.

Step-by-step solution

Given: Length = 2 × width + 3; Perimeter = 24 cm
To find: The length and the width

Idea: “Three more than twice the width” means 2w + 3. Perimeter of a rectangle = 2(length + width).

  1. Let the width be w cm. Then the length is (2w + 3) cm.½ mark
  2. Perimeter: 2[(2w + 3) + w] = 24, so 2(3w + 3) = 24.1 mark
  3. 3w + 3 = 12, so 3w = 9 and w = 3.1 mark
  4. Width = 3 cm; length = 2 × 3 + 3 = 9 cm.½ mark
The rectangle is 9 cm long and 3 cm wide.

Check: 2(9 + 3) = 24 ✓ and 9 = 2 × 3 + 3 ✓.

Answer to write in the exam

Let width = w cm; length = (2w + 3) cm

2[(2w + 3) + w] = 24

3w + 3 = 12 ⇒ 3w = 9 ⇒ w = 3

Length = 2(3) + 3 = 9

∴ Length = 9 cm, width = 3 cm

Common mistakes that cost marks

  • Writing the length as 3(2w) or 2(w + 3). “Three more than twice the width” is 2w + 3.
  • Using perimeter = length + width = 24. The perimeter has two lengths and two widths.
  • Giving only w = 3 and forgetting to find the length.

How this can come in the exam

MCQ (1 mark)

The length of a rectangle is 4 cm more than its width and its perimeter is 40 cm. Its width is

  1. 8 cm
  2. 12 cm
  3. 18 cm
  4. 9 cm
Show answer

(A) 8 cm
2(w + 4 + w) = 40, so 2w + 4 = 20 and w = 8 cm.

Short answer (3 marks)

The length of a rectangular field is 5 m less than three times its width. The perimeter is 150 m. Find the dimensions.

Show answerLength = 3w − 5 (½ mark). 2(3w − 5 + w) = 150, so 4w − 5 = 75 (1 mark). w = 20 m (1 mark), length = 55 m (½ mark).

Try one yourself

The length of a rectangle is one more than three times its width, and its perimeter is 42 cm. Find its dimensions.

Show answer

2(3w + 1 + w) = 42, so 4w + 1 = 21 and w = 5. Width 5 cm, length 16 cm.

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