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Linear patterns · 3 marks

An auto-rikshaw fare starts at ₹25 and remains the same for the initial 2 km. Then it increases by ₹15 per km. What will be the fare for a travel of 10 km?

Answer: Fare = 25 + 15 × (10 − 2) = 25 + 120 = ₹145. In general, for n km (n ≥ 2) the fare is ₹(15n − 5).

Step-by-step solution

Given: ₹25 for the first 2 km; ₹15 for every km after that
To find: The fare for 10 km

Idea: The first 2 km cost a fixed ₹25. Only the kilometres after the first 2 are charged at ₹15 each.

  1. For 10 km, the extra kilometres beyond the first 2 are 10 − 2 = 8 km.1 mark
  2. Fare = 25 + 15 × 8 = 25 + 120 = ₹145.1 mark
  3. Table of fares:
    Km travelled123456
    Fare (₹)252525 + 1 × 15 = 4025 + 2 × 15 = 5525 + 3 × 15 = 7025 + 4 × 15 = 85
  4. In general, for n km (n ≥ 2): fare = 25 + 15(n − 2) = 25 + 15n − 30 = ₹(15n − 5). The fare is a function of the distance. Check: 15 × 10 − 5 = 145 ✓.1 mark
The fare for 10 km is ₹145.

Check: Formula 15n − 5 at n = 10: 150 − 5 = 145 ✓. At n = 6: 85, which matches the table ✓.

Answer to write in the exam

Distance after the first 2 km = 10 − 2 = 8 km

Fare = 25 + 15 × 8 = 25 + 120

In general, fare for n km (n ≥ 2) = 25 + 15(n − 2) = ₹(15n − 5)

∴ Fare for 10 km = ₹145

Common mistakes that cost marks

  • Charging ₹15 for all 10 km: 25 + 150 = ₹175. The first 2 km are already covered by the ₹25.
  • Using 10 × 15 = ₹150 and forgetting the starting fare.
  • Writing the general fare as 25 + 15n instead of 25 + 15(n − 2).

How this can come in the exam

MCQ (1 mark)

A taxi charges ₹50 for the first 3 km and ₹12 for each km after that. The fare for 13 km is

  1. ₹156
  2. ₹170
  3. ₹206
  4. ₹120
Show answer

(B) ₹170
50 + 12 × (13 − 3) = 50 + 120 = ₹170.

Case-based (4 marks)

A parking lot charges ₹30 for the first hour and ₹20 for every hour after that.
(i) Find the charge for 1 hour and for 4 hours. (ii) Write the charge for h hours (h ≥ 1). (iii) Find the charge for 9 hours. (iv) A driver paid ₹250. How long did she park?

Show answer(i) ₹30; 30 + 20 × 3 = ₹90 (1 mark). (ii) 30 + 20(h − 1) = ₹(20h + 10) (1 mark). (iii) 20 × 9 + 10 = ₹190 (1 mark). (iv) 20h + 10 = 250 ⇒ h = 12 hours (1 mark).

Try one yourself

Using the same auto-rickshaw fares, find the fare for 7 km and for 15 km.

Show answer

15 × 7 − 5 = ₹100; 15 × 15 − 5 = ₹220.

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