Bela has ₹100 for pocket money. She spends ₹5 every day. Observe that the amount left on the nth day will be ₹(100 − 5n).
What amount will be left on the 15th day? How many days will it take for the entire amount to be spent?
Step-by-step solution
Idea: Put n = 15 into 100 − 5n. “The entire amount is spent” means the amount left is 0, so solve 100 − 5n = 0.
- 15th day: 100 − 5 × 15 = 100 − 75 = ₹25.1 mark
- All spent: 100 − 5n = 0 ⇒ 5n = 100 ⇒ n = 20.½ mark
- It takes 20 days to spend the whole ₹100.½ mark
Check: 20 days × ₹5 = ₹100 ✓.
Answer to write in the exam
Amount left on nth day = ₹(100 − 5n)
15th day: 100 − 5(15) = 100 − 75 = 25
100 − 5n = 0 ⇒ 5n = 100 ⇒ n = 20
∴ ₹25 is left on the 15th day; the money lasts 20 days
Common mistakes that cost marks
- Giving ₹75 for the 15th day. ₹75 is what she has spent; the question asks what is left.
- Solving 100 − 5n = 0 as n = 100 − 5 = 95.
- Answering 21 days by counting day 0 as a day of spending.
How this can come in the exam
A candle is 30 cm long and burns 1.5 cm every hour. It burns out completely after
- 15 hours
- 20 hours
- 28.5 hours
- 45 hours
Show answer
(B) 20 hours
30 − 1.5h = 0 ⇒ h = 20.
A bus pass has 60 rides and 2 rides are used every day. How many rides remain after 18 days, and after how many days is the pass used up?
Show answer
60 − 2 × 18 = 24 rides (1 mark). 60 − 2d = 0 ⇒ d = 30 days (1 mark).Try one yourself
A pot of rice has 3 kg and 0.25 kg is used each day. How much is left after 8 days, and when will it run out?
Show answer
3 − 0.25 × 8 = 1 kg left. 3 − 0.25d = 0 ⇒ d = 12 days.
More questions like this
- An auto-rikshaw fare starts at ₹25 and remains the same for the initial 2 km. Then it increases by ₹15 per km. What will be the fare for a travel of 10 km?
- Observe that the total fare for a travel of n km will be ₹25 + 15 × (n − 2) = 15n − 5, when n ≥ 2.
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