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Integers · 2 marks

A spice trader takes a loan (debt) of ₹850. The next day, he makes a profit (fortune) of ₹1,200. The following week, he incurs a loss of ₹450. Write this sequence as an equation using integers and calculate his final financial standing.

Answer: (−850) + 1200 + (−450) = −100. He is left with a debt of ₹100.

Step-by-step solution

Idea: Write debts and losses as negative integers and profits as positive integers, then add them in order.

  1. Loan (debt) of ₹850 → −850. Profit of ₹1,200 → +1200. Loss of ₹450 → −450.½ mark
  2. Equation: (−850) + 1200 + (−450) = x, where x is his final standing.½ mark
  3. (−850) + 1200 = 350 (the profit clears the loan and leaves ₹350). Then 350 + (−450) = −100.½ mark
  4. x = −100: his final standing is a debt of ₹100.½ mark
(−850) + 1200 + (−450) = −100. He finally owes ₹100 (a debt of ₹100).

Check: Total gains 1200, total debts and losses 850 + 450 = 1300; 1200 − 1300 = −100 ✓.

Answer to write in the exam

Loan = −850, profit = +1200, loss = −450

Final standing = (−850) + 1200 + (−450)

= 350 + (−450)

= −100

∴ He has a debt of ₹100.

Common mistakes that cost marks

  • Writing the loan as +850, because he ‘receives’ money. A loan is a debt, so it is −850.
  • Getting the size right but the sign wrong: answering ‘₹100 profit’.
  • Adding all three as positives: 850 + 1200 + 450 = 2500.

How this can come in the exam

MCQ (1 mark)

A shop owner gains ₹500 on Monday, loses ₹720 on Tuesday and gains ₹150 on Wednesday. His net result is

  1. ₹70 profit
  2. ₹70 loss
  3. ₹1370 profit
  4. ₹370 loss
Show answer

(B) ₹70 loss
500 − 720 + 150 = −70, a loss of ₹70.

Case-based (4 marks)

A school canteen starts the month with a debt of ₹1,500 to its supplier. In week 1 it earns ₹2,300, in week 2 it pays ₹900 for repairs, and in week 3 it earns ₹650.
(i) Write the debt and the repairs as integers. (ii) Write one equation for the canteen’s position after week 3. (iii) Find the position. (iv) Is the canteen in debt or in profit?

Show answer(i) −1500 and −900 (1 mark). (ii) (−1500) + 2300 + (−900) + 650 = x (1 mark). (iii) x = 550 (1 mark). (iv) In profit: it has ₹550 after clearing the debt (1 mark).

Try one yourself

Meena owes ₹300, then earns ₹480, then spends ₹260. Write an integer equation for her position and solve it.

Show answer

(−300) + 480 + (−260) = −80: she owes ₹80.

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