What would a system of coordinates be like if we did not have negative numbers? Would this system allow us to locate all the points on a 2-D plane?
Step-by-step solution
Idea: Negative coordinates are what describe the points to the left of the y-axis and below the x-axis. Without them, three of the four quadrants disappear.
- Without negative numbers, both coordinates must be 0 or positive. So the only points we could describe are on the positive x-axis, the positive y-axis, or in Quadrant I.½ mark
- Points in Quadrants II, III and IV, and on the negative halves of the axes, such as (−3, 0) or (2, −5), could not be written at all.½ mark
- We could move the origin to the bottom-left corner of a region (as on a computer screen or a page of graph paper), but that covers only that limited region. The plane goes on forever in every direction, so some points would always be left out.½ mark
- So no, such a system could not locate all the points of the plane. This is why zero and negative numbers are essential for the four-quadrant plane.½ mark
Check: Of the four sign patterns (+, +), (−, +), (−, −), (+, −), only (+, +) survives without negative numbers: one quadrant out of four ✓.
Answer to write in the exam
Without negative numbers: x ≥ 0 and y ≥ 0 only
Only Quadrant I and the positive halves of the axes can be described.
Points like (−3, 0), (−2, 4), (2, −5) cannot be described.
Moving the origin covers only a limited region; the plane is unlimited.
∴ No, not all points of the plane could be located.
Common mistakes that cost marks
- Saying “yes, just move the origin”. Moving the origin helps only for a limited region; the plane has no edge.
- Thinking only Quadrant III is lost. Any point with even one negative coordinate is lost: Quadrants II, III and IV.
- Forgetting that 0 is still allowed, so points on the positive halves of the axes can still be described.
How this can come in the exam
If only non-negative numbers could be used as coordinates, which of these points could be described?
- (−1, 4)
- (4, −1)
- (0, 4)
- (−4, −1)
Show answer
(C) (0, 4)
(0, 4) has no negative coordinate; each of the others has at least one.
Assertion (A): Using only non-negative coordinates, the point 3 units to the left of the origin cannot be described.
Reason (R): Without negative numbers, coordinates can describe only points on or to the right of the y-axis and on or above the x-axis.
- Both A and R are true, and R is the correct explanation of A.
- Both A and R are true, but R is not the correct explanation of A.
- A is true but R is false.
- A is false but R is true.
Show answer
(A) Both A and R are true, and R is the correct explanation of A.
The point is (−3, 0), which needs a negative x-coordinate; R explains why it cannot be described.
Try one yourself
The origin is moved to the point that used to be (−10, −10), and only non-negative coordinates are allowed. What are the new coordinates of the old points (−4, 3) and (0, 0)? Can the old point (−12, 5) be described?
Show answer
New coordinates are old + 10 in each place: (6, 13) and (10, 10). The old point (−12, 5) would become (−2, 15), which needs a negative number, so no.
More questions like this
- Are the points M (−3, −4), A (0, 0) and G (6, 8) on the same straight line? Suggest a method to check this without plotting and joining the points.
- Use your method (the one used for M (−3, −4), A (0, 0) and G (6, 8)) to check if the points R (−5, −1), B (−2, −5) and C (4, −12) are on the same straight line. Now plot both sets of points and check your answers.
- Using the origin as one vertex, plot the vertices of:
- The following table shows the coordinates of points S, M and T. In each case, state whether M is the midpoint of segment ST. Justify your answer.
- Use the connection you found to find the coordinates of B given that M (−7, 1) is the midpoint of A (3, −4) and B (x, y).