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Midpoint of a segment · 2 marks

Use the connection you found to find the coordinates of B given that M (−7, 1) is the midpoint of A (3, −4) and B (x, y).

Answer: B = (−17, 6), since 3 + x2 = −7 gives x = −17 and −4 + y2 = 1 gives y = 6.

Step-by-step solution

Given: Midpoint M (−7, 1); One end A (3, −4); other end B (x, y)
To find: B

Idea: The midpoint’s coordinates are the averages of the end points’ coordinates: M = (x1 + x22, y1 + y22). Knowing M and one end, solve for the other end.

  1. x-coordinates: 3 + x2 = −7, so 3 + x = −14 and x = −17.½ mark
  2. y-coordinates: −4 + y2 = 1, so −4 + y = 2 and y = 6.½ mark
  3. So B = (−17, 6).½ mark
  4. Check: midpoint of A (3, −4) and B (−17, 6) = ((3 − 17) ÷ 2, (−4 + 6) ÷ 2) = (−7, 1) = M ✓.½ mark
B = (−17, 6).

Check: Going from A to M is a shift of (−10, +5); going the same shift again from M gives (−7 − 10, 1 + 5) = (−17, 6) = B ✓.

Answer to write in the exam

M = (x1 + x22, y1 + y22)

3 + x2 = −7 ⇒ 3 + x = −14 ⇒ x = −17

−4 + y2 = 1 ⇒ −4 + y = 2 ⇒ y = 6

∴ B = (−17, 6)

Common mistakes that cost marks

  • Averaging A and M instead: ((3 − 7) ÷ 2, (−4 + 1) ÷ 2) = (−2, −1.5). M is the midpoint, so solve for B.
  • Forgetting to multiply by 2: writing 3 + x = −7, so x = −10.
  • Sign slip: −4 + y = 2 gives y = 6, not −2.

How this can come in the exam

MCQ (1 mark)

If (2, 3) is the midpoint of the segment joining (−1, y) and (x, 5), then (x, y) =

  1. (5, 1)
  2. (1, 5)
  3. (3, −2)
  4. (5, −1)
Show answer

(A) (5, 1)
(−1 + x) ÷ 2 = 2 gives x = 5; (y + 5) ÷ 2 = 3 gives y = 1.

Short answer (2 marks)

The centre of a circle is (2, −3) and one end of a diameter is (−4, 5). Find the other end of the diameter.

Show answerThe centre is the midpoint of the diameter (½ mark). (−4 + x) ÷ 2 = 2 ⇒ x = 8; (5 + y) ÷ 2 = −3 ⇒ y = −11 (1 mark). Other end (8, −11) (½ mark).

Try one yourself

M (0, 4) is the midpoint of A (−6, 9) and B. Find B.

Show answer

(−6 + x) ÷ 2 = 0 ⇒ x = 6; (9 + y) ÷ 2 = 4 ⇒ y = −1. B = (6, −1).

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