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100% stacked bar charts · 4 marks

The 100% stacked bar below compares the proportion of flowers blooming in Fatima’s garden and Naveen’s garden across seasons. Which of the following statements can be inferred from this chart?
(Hint: Find out the blooms per season in each garden if both the gardens had the same total number of blooms over the year. Similarly find out what happens if the totals are very different.)

  1. (i) In Fatima’s garden, there were more blooms in the summer than in the monsoon.
  2. (ii) In summer, Fatima’s garden had more blooms than Naveen’s garden.
  3. (iii) In winter, Fatima’s garden had fewer blooms than Naveen’s garden.
  4. (iv) The total number of flowers, across seasons, is the same in both gardens but it varies in each season.
Proportion of flowers that bloomedacross seasonsSummerMonsoonWinterFatima50%30%20%Naveen40%25%35%0%25%50%75%100%
Answer: Only (i) can be inferred. (ii) and (iii) compare numbers across gardens and (iv) is about totals, but a 100% stacked bar shows only fractions within each garden, not actual numbers.

Step-by-step solution

Idea: Each bar is that garden’s own total, taken as 100%. Comparing pieces within one bar compares real numbers; comparing pieces across bars does not, because the two totals may be different.

Case 1: number of flowersSummerMonsoonWinterFatima1056342Naveen483042050100150200250Case 2: number of flowersSummerMonsoonWinterFatima905436Naveen966084050100150200250

(i) In Fatima’s garden, there were more blooms in the summer than in the monsoon.

  1. Same garden, same total: 50% of her flowers is more than 30% of the same flowers. Can be inferred (true).1 mark
Can be inferred

(ii) In summer, Fatima’s garden had more blooms than Naveen’s garden.

  1. 50% of Fatima’s total vs 40% of Naveen’s total. If the totals are 210 and 120 (Case 1): 105 > 48. If the totals are 180 and 240 (Case 2): 90 < 96. It can go either way, so it cannot be inferred.1 mark
Cannot be inferred

(iii) In winter, Fatima’s garden had fewer blooms than Naveen’s garden.

  1. 20% of Fatima’s total vs 35% of Naveen’s. In Case 1 both are 42 (not fewer); in Case 2, 36 < 84. Without the totals we cannot tell, so it cannot be inferred.1 mark
Cannot be inferred

(iv) The total number of flowers, across seasons, is the same in both gardens but it varies in each season.

  1. Every bar in a 100% chart has the same length whatever its total, so the chart says nothing about whether the totals are equal (Case 1 has 210 and 120; Case 2 has 180 and 240). Cannot be inferred.1 mark
Cannot be inferred
Only statement (i) can be inferred. Statements (ii), (iii) and (iv) need the actual totals, which a 100% stacked bar chart does not show.

Check: Case 1: 105210 = 50%, 63210 = 30%, 42210 = 20%; 48120 = 40%, 30120 = 25%, 42120 = 35% ✓. Case 2: 90180 = 50%, 96240 = 40%, 84240 = 35% ✓. (The chart gives Naveen 25% in monsoon and 35% in winter.)

Answer to write in the exam

(i)

Fatima: summer 50%, monsoon 30% of the same total

∴ (i) can be inferred

(ii)

Case 1: Fatima 105, Naveen 48 (Fatima more)

Case 2: Fatima 90, Naveen 96 (Naveen more)

∴ (ii) cannot be inferred

(iii)

Case 1: Fatima 42, Naveen 42 (equal)

Case 2: Fatima 36, Naveen 84

∴ (iii) cannot be inferred

(iv)

100% bars always have equal length

Totals could be 210 and 120, or 180 and 240

∴ (iv) cannot be inferred

Common mistakes that cost marks

  • Accepting (ii) because 50% is more than 40%. Percentages of different totals cannot be compared as numbers of flowers.
  • Thinking equal bar lengths mean equal totals, as in (iv).
  • Mixing up Naveen’s monsoon (25%) and winter (35%) pieces; read the colours from the legend.

How this can come in the exam

MCQ (1 mark)

A 100% stacked bar shows that 60% of School P’s students and 45% of School Q’s students walk to school. Which conclusion is valid?

  1. More students walk in P than in Q
  2. P has more students than Q
  3. In P, more students walk than do not walk
  4. Fewer students walk in Q than in P
Show answer

(C) In P, more students walk than do not walk
Within P, 60% walk and 40% do not, so more walk. The others compare different totals.

Short answer (2 marks)

Give totals for which 40% of Garden X’s flowers is more than 60% of Garden Y’s flowers.

Show answerTake X = 300 and Y = 100: 40% of 300 = 120 > 60% of 100 = 60 (any totals with 0.4X > 0.6Y; 2 marks).

Try one yourself

A 100% bar shows 70% of a shop’s sales in March were online and 55% in April. Can we say online sales fell in April?

Show answer

No. If total sales in April were much larger, 55% of it could be more than 70% of March’s total. We only know the share fell.

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