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Weighted mean · 3 marks

Suvarna had purchased 1g gold at ₹15k (short for ₹15,000). This is shown by point O denoting the average price of gold that she possesses. Six different scenarios are given below for her next transaction. For each scenario estimate and mark the average price of gold she will have after the transaction.

  1. (i) Purchase 1g gold at ₹30k
  2. (ii) Purchase 2g gold at ₹30k
  3. (iii) Purchase 1g gold at ₹10k
  4. (iv) Purchase 10g gold at ₹10k
  5. (v) Purchase 0.5g gold at ₹30k
  6. (vi) Purchase 0.5g gold at ₹15k
051015202530Average price of 1 g of gold (₹ thousand)O
Answer: (i) ₹22.5k (ii) ₹25k (iii) ₹12.5k (iv) ≈ ₹10.45k (v) ₹20k (vi) ₹15k (stays at O).

Step-by-step solution

Idea: New average = 1 × 15 + (grams bought) × (price)1 + grams bought. The new point lies between O (15) and the new price, closer to whichever side has more grams.

051015202530Average price of 1 g of gold (₹ thousand)(i)(ii)(iii)(iv)(v)O, (vi)

(i) Purchase 1g gold at ₹30k

  1. Equal amounts (1 g each): midway, 15 + 302 = 22.5.½ mark
₹22.5k

(ii) Purchase 2g gold at ₹30k

  1. More weight on 30: 15 + 2 × 303 = 753 = 25 (two-thirds of the way from 15 to 30).½ mark
₹25k

(iii) Purchase 1g gold at ₹10k

  1. Equal amounts: 15 + 102 = 12.5.½ mark
₹12.5k

(iv) Purchase 10g gold at ₹10k

  1. 10 g at 10 against 1 g at 15: very close to 10. 15 + 10011 = 11511 ≈ 10.45.½ mark
≈ ₹10.45k

(v) Purchase 0.5g gold at ₹30k

  1. Less weight on 30: 15 + 0.5 × 301.5 = 301.5 = 20 (one-third of the way from 15 to 30).½ mark
₹20k

(vi) Purchase 0.5g gold at ₹15k

  1. Same price as her average, so the average does not move: 15 (still at O).½ mark
₹15k (at O)
(i) 22.5 (ii) 25 (iii) 12.5 (iv) about 10.45 (v) 20 (vi) 15, all in thousands of rupees per gram.

Check: Each answer lies between 15 and the new price ✓; the more grams bought, the closer to the new price ((ii) closer to 30 than (i); (iv) closer to 10 than (iii)) ✓.

Answer to write in the exam

(i)

1 × 15 + 1 × 302 = 22.5

∴ ₹22.5k

(ii)

1 × 15 + 2 × 303 = 753 = 25

∴ ₹25k

(iii)

1 × 15 + 1 × 102 = 12.5

∴ ₹12.5k

(iv)

1 × 15 + 10 × 1011 = 11511 = 10.45

∴ ≈ ₹10.45k

(v)

1 × 15 + 0.5 × 301.5 = 301.5 = 20

∴ ₹20k

(vi)

1 × 15 + 0.5 × 151.5 = 15

∴ ₹15k (point O)

Common mistakes that cost marks

  • Taking the midpoint every time. Only when equal amounts are bought is the new average midway.
  • In (vi), thinking any purchase changes the average. Buying at the average price leaves it unchanged.
  • In (v), dividing by 2 instead of 1 + 0.5 = 1.5 grams.

How this can come in the exam

MCQ (1 mark)

Ravi has 2 g of gold at an average of ₹12k per gram and buys 2 g at ₹18k per gram. His new average is

  1. ₹15k
  2. ₹14k
  3. ₹16k
  4. ₹30k
Show answer

(A) ₹15k
Equal amounts: 12 + 182 = 15.

Try one yourself

Suvarna has 1 g of gold at ₹15k. She buys 3 g at ₹11k. Find her new average price.

Show answer

15 + 334 = 484 = ₹12k per gram.

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