Given some data with corresponding weights, how would the weighted average change if all the weights are doubled? If required, experiment with some data. What do you observe? Justify your answer using algebra.
Step-by-step solution
Idea: Only the ratio of the weights matters. Weights 3 : 2 : 5 and 6 : 4 : 10 are the same ratio.
- Experiment: marks 60, 64, 73 with weights 3, 2, 5 give 180 + 128 + 36510 = 67.3. With weights 6, 4, 10: 360 + 256 + 73020 = 134620 = 67.3. Same.1 mark
- Algebra: new average = (2w1)x1 + (2w2)x2 + … + (2wn)xn2w1 + 2w2 + … + 2wn = 2(w1x1 + … + wnxn)2(w1 + … + wn).1 mark
- Cancel the common factor 2: it equals the original weighted average. Observation: doubling (indeed, multiplying all weights by any positive number) does not change the weighted average; only the ratio of the weights matters.1 mark
Answer to write in the exam
Original: x̄ = ΣwixiΣwi
New: Σ(2wi)xiΣ2wi = 2Σwixi2Σwi = ΣwixiΣwi
e.g. 60, 64, 73 with weights 3, 2, 5 or 6, 4, 10: both give 67.3
∴ The weighted average does not change
Common mistakes that cost marks
- Thinking the average doubles. The denominator doubles too.
- Doubling the weights in the numerator only.
- Confusing this with adding the same number to every weight, which does change the average.
How this can come in the exam
Assertion (A): Weights 1 : 2 : 3 and 10 : 20 : 30 give the same weighted mean for any data.
Reason (R): Multiplying all weights by the same positive number does not change the weighted mean.
- Both A and R are true, and R is the correct explanation of A.
- Both A and R are true, but R is not the correct explanation of A.
- A is true but R is false.
- A is false but R is true.
Show answer
(A) Both A and R are true, and R is the correct explanation of A.
10 : 20 : 30 is 10 times 1 : 2 : 3; the factor 10 cancels, so R explains A.
Try one yourself
Find the weighted mean of 4, 8, 10 with weights 1, 1, 2 and then with weights 5, 5, 10.
Show answer
4 + 8 + 204 = 8 and 20 + 40 + 10020 = 8: the same.
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