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Average of averages · 2 marks

Shreyas calculated it differently as (165.5 × 8) + (149.33 × 3)8 + 3 = 1324 + 44811 = 177211 = 161.09. Do you understand why this also works? Can you see why 165.5 × 8 gives the sum of the heights of all the seniors and 149.33 × 3 gives the sum of the heights of all the juniors?

Answer: Since average = sumnumber of values, we get sum = average × number of values. So 165.5 × 8 = 1324 cm is the total height of the 8 seniors and 149.33 × 3 ≈ 448 cm is the total of the 3 juniors. Adding them gives the total of all 11 heights, and dividing by 11 gives the correct average, 161.09 cm.

Step-by-step solution

Given: 8 seniors, average height 165.5 cm; 3 juniors, average height 149.33 cm

Idea: An average can be ‘undone’: multiplying an average by the number of values gives back the sum of those values. Then the combined average is the total sum divided by the total number.

  1. Average of the seniors = sum of seniors’ heights8 = 165.5. Multiply both sides by 8: sum of seniors’ heights = 165.5 × 8 = 1324 cm. (Check: 165 + 169 + 164 + 167 + 170 + 159 + 164 + 166 = 1324 ✓.)½ mark
  2. In the same way, sum of the juniors’ heights = 149.33 × 3 = 447.99 ≈ 448 cm (the exact sum is 146 + 149 + 153 = 448; 149.33 is a rounded average).½ mark
  3. So the numerator 1324 + 448 = 1772 is the sum of all 11 heights, and the denominator 8 + 3 = 11 is the number of trainees.½ mark
  4. Sum of all heights ÷ number of trainees is exactly the definition of the average, so Shreyas’s method gives the correct 1772 ÷ 11 = 161.09 cm. In general, two groups with averages a, b and sizes n, m have combined average an + bmn + m.½ mark
Yes. Average × number of values = sum of the values, so 165.5 × 8 = 1324 is the seniors’ total height and 149.33 × 3 ≈ 448 is the juniors’ total. Their sum, 1772, divided by 11 trainees gives the same correct average, 161.09 cm.

Answer to write in the exam

Average = sum of valuesnumber of values ⇒ sum = average × number

Sum of seniors’ heights = 165.5 × 8 = 1324 cm

Sum of juniors’ heights = 149.33 × 3 ≈ 448 cm

Average of group = 1324 + 4488 + 3 = 177211 = 161.09 cm

∴ Shreyas’s method gives the total of all heights ÷ total number, so it is correct

Common mistakes that cost marks

  • Thinking 149.33 × 3 = 447.99 means the method is slightly wrong. 149.33 is rounded; the exact juniors’ total is 448.
  • Dividing by 2 at the end instead of by 8 + 3 = 11.
  • Multiplying each average by the other group’s size (165.5 × 3), which gives a meaningless number.

How this can come in the exam

MCQ (1 mark)

The average of 12 numbers is 25. The sum of the 12 numbers is

  1. 37
  2. 300
  3. 250
  4. 2.08
Show answer

(B) 300
Sum = average × number = 25 × 12 = 300.

Try one yourself

The average weight of 5 bags is 18 kg and of 7 other bags is 24 kg. Find the total weight of all 12 bags and their average weight.

Show answer

Totals: 5 × 18 = 90 kg and 7 × 24 = 168 kg, so all 12 bags weigh 258 kg. Average = 258 ÷ 12 = 21.5 kg.

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