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Running track and stagger · 3 marks

In my school, the playground is too small to have a 400 m track, so the school constructed a 200 m track instead. Does this mean that we need a smaller stagger for the race tracks in my school (i.e., smaller than the stagger used in the Olympics), for the same 4 × 100 m relay race?

Answer: No. The extra length of an outer lane does not depend on how big the bend is, only on the lane width and how much turning the race has. A 4 × 100 m relay is two laps of a 200 m track, so it has twice as many bends: the stagger is about double (about 15.3 m instead of about 7.7 m for 1.22 m lanes).

Step-by-step solution

Idea: For a lane of width w, a half-turn (semicircular bend) adds π(r + w) − πr = πw, whatever the radius r. So the stagger depends on the number of bends in the race, not on the size of the track.

  1. On a semicircular bend of inner radius r, the next lane out is longer by π(r + w) − πr = πw. The radius r cancels, so a small track and a big track give the same extra length per bend.1 mark
  2. 400 m track: one lap = 400 m has 2 semicircular bends. Stagger between neighbouring lanes = 2 × πw = 2πw. With w = 1.22 m: 2 × 3.1416 × 1.22 ≈ 7.67 m.½ mark
  3. 200 m track: 400 m = 2 laps, so the race has 4 semicircular bends. Stagger = 4 × πw = 4πw ≈ 4 × 3.1416 × 1.22 ≈ 15.33 m.1 mark
  4. So the school does not need a smaller stagger. It needs one about twice as large, because its relay runs round twice as many bends.½ mark
No. The stagger per bend is π × (lane width), independent of the size of the track. On a 200 m track the 4 × 100 m relay goes round 4 bends instead of 2, so the stagger must be about twice the Olympic one (about 15.3 m instead of about 7.7 m for 1.22 m lanes).

Check: Each full lap on any track has one full turn, adding 2πw. Two laps add 4πw, twice one lap’s 2πw ✓.

Answer to write in the exam

Extra length per semicircular bend = π(r + w) − πr = πw (independent of r).

400 m track: 400 m = 1 lap = 2 bends ⇒ stagger = 2πw ≈ 2 × 3.1416 × 1.22 ≈ 7.67 m.

200 m track: 400 m = 2 laps = 4 bends ⇒ stagger = 4πw ≈ 15.33 m.

∴ No; the stagger is not smaller, it is about twice as large.

Common mistakes that cost marks

  • Thinking a smaller track means smaller staggers. The radius cancels; only the lane width and the number of bends matter.
  • Forgetting that 400 m on a 200 m track is two laps, so it has 4 bends, not 2.
  • Using the lane radius instead of the lane width in πw.

How this can come in the exam

Assertion–Reason (1 mark)

Assertion (A): On a semicircular bend, the extra length of a lane of width w over the lane just inside it is the same on a small track and on a large track.
Reason (R): π(r + w) − πr = πw, which does not contain r.

  1. Both A and R are true, and R is the correct explanation of A.
  2. Both A and R are true, but R is not the correct explanation of A.
  3. A is true but R is false.
  4. A is false but R is true.
Show answer

(A) Both A and R are true, and R is the correct explanation of A.
The difference of the two semicircle lengths is πw; the radius cancels. R explains A.

Short answer (2 marks)

A race on a small track goes round 6 semicircular bends in lanes 1 m wide. Find the stagger between neighbouring lanes. (Use π = 227.)

Show answerExtra per bend = π × 1 = 227 m (1 mark). Stagger = 6 × 227 = 1327 ≈ 18.86 m (1 mark).

Try one yourself

A race covers 3 semicircular bends in lanes 1.5 m wide. What stagger is needed between neighbouring lanes? (Use π = 3.14.)

Show answer

3 × π × 1.5 = 3 × 3.14 × 1.5 = 14.13 m.

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