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Running track and stagger · 2 marks

What is the connection between this question and the one about the 400 m athletics track?

Answer: The curved ends of a running track are semicircles. To find how long each lane is, and so how big the stagger must be, we need the perimeter of a circle. Two semicircular ends together make one full circle of length 2πr.

Step-by-step solution

Idea: “This question” is: what is the perimeter of a circle of radius r? The track question needs exactly this, because lanes differ only on the curved parts.

  1. A 400 m track has two straight parts and two curved ends. The curved ends are semicircles, and together they make one full circle.1 mark
  2. The straights are the same for every lane, so the difference between lanes comes only from the circles. Lane of radius r: curved length 2πr. The stagger is the difference 2π(r + w) − 2πr. So answering the track question needs the perimeter of a circle.1 mark
The track’s curved ends are semicircles, so the length of each lane, and the stagger between lanes, are found from the perimeter (circumference) of a circle.

Answer to write in the exam

Curved ends of the track = 2 semicircles = 1 full circle.

Straight parts equal for all lanes.

Difference between lanes = 2π(r + w) − 2πr.

∴ Stagger needs the perimeter of a circle.

Common mistakes that cost marks

  • Thinking the straight parts cause the stagger. The straights are equal in all lanes.
  • Treating the two ends as two full circles. Each end is a semicircle.

How this can come in the exam

Short answer (2 marks)

A track has two straight parts of 100 m each and two semicircular ends, each of radius 35 m (measured along the inner edge). Find the length of the inner edge. (Use π = 227.)

Show answerTwo semicircles = one circle: 2 × 227 × 35 = 220 m (1 mark). Total = 200 + 220 = 420 m (1 mark).

Try one yourself

A path has two straight parts of 50 m and two semicircular ends of radius 14 m. Find its total length. (Use π = 227.)

Show answer

2 × 50 + 2 × 227 × 14 = 100 + 88 = 188 m.

More questions like this

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