If a and b are perfect squares, then ab is a perfect square.
Step-by-step solution
Idea: Write the squares in general form to prove the proposition. For the converse, two non-squares can still multiply to a square, e.g. 2 × 8.
- Converse: If ab is a perfect square, then a and b are perfect squares.½ mark
- Proposition — true. Let a = m2 and b = k2 for whole numbers m, k. Then ab = m2k2 = (mk)2, a perfect square. E.g. 4 × 9 = 36 = 62.1 mark
- Converse — false. Take a = 2 and b = 8. Then ab = 16 = 42, a perfect square.½ mark
- But 2 and 8 are not perfect squares (12 = 1, 22 = 4, 32 = 9). So a = 2, b = 8 is a counterexample.½ mark
- So the proposition is true and its converse is false.½ mark
Answer to write in the exam
Converse: If ab is a perfect square, then a and b are perfect squares.
Proposition: a = m2, b = k2 ⇒ ab = m2k2 = (mk)2. True.
Converse: a = 2, b = 8: ab = 16 = 42
2 and 8 are not perfect squares.
∴ Proposition true; converse false.
Common mistakes that cost marks
- Testing the converse with a = 4, b = 9. Both are squares, so this agrees with the converse and proves nothing.
- Proving the proposition with one example (4 × 9 = 36). Use m2k2 = (mk)2 to cover every case.
How this can come in the exam
Which pair is a counterexample to ‘If ab is a perfect square, then a and b are perfect squares’?
- 4 and 25
- 3 and 12
- 9 and 16
- 1 and 49
Show answer
(B) 3 and 12
3 × 12 = 36 = 62, but neither 3 nor 12 is a perfect square. In the other pairs both numbers are squares.
Is ‘If a and b are perfect cubes, then ab is a perfect cube’ true? Justify.
Show answer
True. Let a = m3, b = k3 (1 mark). Then ab = m3k3 = (mk)3, a perfect cube; e.g. 8 × 27 = 216 = 63 (1 mark).Try one yourself
Give a counterexample to ‘If a + b is a perfect square, then a and b are perfect squares’.
Show answer
a = 7, b = 9: a + b = 16 = 42, but 7 is not a perfect square.