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Graphical method · 4 marks

Form a pair of linear equations and find their common solutions graphically.
10 students took part in a Mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.

Answer: x + y = 10 and x − y = 4 (x = girls, y = boys). The lines meet at (7, 3): 7 girls and 3 boys.

Step-by-step solution

Idea: Draw both lines from a small table of values and read off the point where they cross.

x (girls)y (boys)246810−22468100x + y = 10x − y = 4(0, 10)(5, 5)(4, 0)(6, 2)(7, 3)
  1. Let the number of girls be x and boys y. Total: x + y = 10. Girls are 4 more: x − y = 4.1 mark
  2. Tables:
    x + y = 10:
    x0510
    y1050
    x − y = 4:
    x467
    y023
    1 mark
  3. Plot the points and draw the two lines (see the graph). They intersect at (7, 3).1 mark
  4. So x = 7, y = 3: 7 girls and 3 boys took part.1 mark
7 girls and 3 boys (the lines x + y = 10 and x − y = 4 meet at (7, 3)).

Check: 7 + 3 = 10 ✓ and 7 − 3 = 4 ✓.

Answer to write in the exam

Let girls = x, boys = y

x + y = 10 … (1); x − y = 4 … (2)

(1):

x0510
y1050

(2):

x467
y023

The lines intersect at (7, 3)

∴ Girls = 7, boys = 3

Common mistakes that cost marks

  • Writing y = x + 4 (boys 4 more than girls), which gives 3 girls and 7 boys.
  • Reading the intersection from a rough sketch as (6, 4); always check the point in both equations.

How this can come in the exam

Short answer (3 marks)

Graphically find two numbers whose sum is 8 and whose difference is 2.

Show answerx + y = 8: (0, 8), (8, 0); x − y = 2: (2, 0), (5, 3) (1 mark). Draw both (1 mark). They meet at (5, 3): numbers 5 and 3 (1 mark).

Try one yourself

In a class of 12 students, boys are 2 fewer than girls. Find each number.

Show answer

g + b = 12, g − b = 2 ⇒ 7 girls, 5 boys.

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