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Consistency of a pair of equations · 3 marks

Given the linear equation 2x + 3y − 8 = 0, write another linear equation in two variables so that the graphs of the pair formed represent (i) intersecting lines (ii) parallel lines (iii) coincident lines.

  1. (i) intersecting lines
  2. (ii) parallel lines
  3. (iii) coincident lines
Answer: (i) 3x − 2y − 7 = 0 (intersecting) (ii) 4x + 6y − 12 = 0 (parallel) (iii) 4x + 6y − 16 = 0 (coincident). Many other answers are possible.

Step-by-step solution

Idea: Intersecting: make a1a2 ≠ b1b2. Parallel: multiply the x– and y-coefficients by the same number but not the constant. Coincident: multiply everything by the same number.

(i) intersecting lines

  1. Take 3x − 2y − 7 = 0: 23 ≠ 3−2, so the lines intersect.1 mark
3x − 2y − 7 = 0

(ii) parallel lines

  1. Take 4x + 6y − 12 = 0: 24 = 36 = 12 but −8−12 = 23 ≠ 12, so the lines are parallel.1 mark
4x + 6y − 12 = 0

(iii) coincident lines

  1. Take 4x + 6y − 16 = 0 (2 × the given equation): 24 = 36 = −8−16 = 12, so the lines are coincident.1 mark
4x + 6y − 16 = 0
(i) 3x − 2y − 7 = 0 (ii) 4x + 6y − 12 = 0 (iii) 4x + 6y − 16 = 0 (other correct answers are possible).

Check: (i) Solving 2x + 3y = 8 and 3x − 2y = 7: 13x = 37, so they do meet at one point (3713, 1013) ✓. (iii) (1, 2) lies on both 2 + 6 − 8 = 0 and 4 + 12 − 16 = 0 ✓.

Answer to write in the exam

(i)

3x − 2y − 7 = 0

a1a2 = 23 ≠ b1b2 = 3−2 ⇒ intersecting lines

(ii)

4x + 6y − 12 = 0

24 = 36 = 12 ≠ −8−12 = 23 ⇒ parallel lines

(iii)

4x + 6y − 16 = 0

24 = 36 = −8−16 = 12 ⇒ coincident lines

Common mistakes that cost marks

  • For parallel lines, multiplying the constant as well (that gives coincident lines).
  • For intersecting lines, choosing 2x + 3y − 5 = 0, which only changes the constant and gives parallel lines.

How this can come in the exam

MCQ (1 mark)

Which line is parallel to x − 2y + 3 = 0?

  1. 2x − 4y + 6 = 0
  2. 2x − 4y + 1 = 0
  3. 2x + 4y + 1 = 0
  4. x + 2y = 3
Show answer

(B) 2x − 4y + 1 = 0
12 = −2−4 ≠ 31.

Try one yourself

Write a line coincident with x + 4y − 2 = 0 and one parallel to it.

Show answer

Coincident: 3x + 12y − 6 = 0; parallel: e.g. 3x + 12y + 1 = 0.

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