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Explicit and recursive rules · 2 marks

Find the 10th and 15th terms of the sequence tn = 5n − 3 for n ≥ 1.

Answer: t10 = 47, t15 = 72.

Step-by-step solution

Idea: In an explicit rule, put the position number in place of n.

  1. t10 = 5 × 10 − 3 = 50 − 3 = 47.1 mark
  2. t15 = 5 × 15 − 3 = 75 − 3 = 72.1 mark
10th term = 47, 15th term = 72.

Check: From the 10th to the 15th term is 5 steps of 5: 47 + 25 = 72 ✓.

Answer to write in the exam

tn = 5n − 3

t10 = 5 × 10 − 3 = 47

t15 = 5 × 15 − 3 = 72

∴ 10th term = 47, 15th term = 72

Common mistakes that cost marks

  • Writing 5 × 10 − 3 as 5 × 7 = 35 (subtracting before multiplying).
  • Listing terms 2, 7, 12, … by hand and miscounting the position.
  • Writing t10 = 10 instead of finding the term in position 10.

How this can come in the exam

MCQ (1 mark)

For tn = 5n − 3, the 21st term is

  1. 102
  2. 105
  3. 108
  4. 100
Show answer

(A) 102
5 × 21 − 3 = 105 − 3 = 102.

Try one yourself

Find the 12th and 30th terms of tn = 4n + 7.

Show answer

t12 = 55, t30 = 127.

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