Find the 10th and 15th terms of the sequence tn = 5n − 3 for n ≥ 1.
Answer: t10 = 47, t15 = 72.
Step-by-step solution
Idea: In an explicit rule, put the position number in place of n.
- t10 = 5 × 10 − 3 = 50 − 3 = 47.1 mark
- t15 = 5 × 15 − 3 = 75 − 3 = 72.1 mark
10th term = 47, 15th term = 72.
Check: From the 10th to the 15th term is 5 steps of 5: 47 + 25 = 72 ✓.
Answer to write in the exam
tn = 5n − 3
t10 = 5 × 10 − 3 = 47
t15 = 5 × 15 − 3 = 72
∴ 10th term = 47, 15th term = 72
Common mistakes that cost marks
- Writing 5 × 10 − 3 as 5 × 7 = 35 (subtracting before multiplying).
- Listing terms 2, 7, 12, … by hand and miscounting the position.
- Writing t10 = 10 instead of finding the term in position 10.
How this can come in the exam
MCQ (1 mark)
For tn = 5n − 3, the 21st term is
- 102
- 105
- 108
- 100
Show answer
(A) 102
5 × 21 − 3 = 105 − 3 = 102.
Try one yourself
Find the 12th and 30th terms of tn = 4n + 7.
Show answer
t12 = 55, t30 = 127.
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