Do you see why the two triangles fit together to make a parallelogram? (If you study the angles in the figure (e.g., ∠B’C’A’ and ∠BCA), you will see why this is so. Keep in mind the criterion by which we check whether two lines are parallel.)
Step-by-step solution
Idea: Two lines are parallel if a transversal makes equal alternate angles with them. The congruent copy supplies exactly those equal angles along the shared side AC.
- Turn the copy A′B′C′ half round and put it on AC so that C′ falls on A and A′ falls on C (possible because C′A′ = CA). Call the position of B′ D.1 mark
- Angles: ∠DAC = ∠B′C′A′ = ∠BCA (congruent triangles). These are alternate angles made by the transversal AC with lines AD and BC, so AD ∥ BC.1 mark
- Similarly ∠DCA = ∠B′A′C′ = ∠BAC, alternate angles for lines DC and AB, so AB ∥ DC. A 4-gon with both pairs of opposite sides parallel is a parallelogram, so ABCD is a parallelogram (and the two triangles fit exactly).1 mark
Answer to write in the exam
Place △A′B′C′ with C′ on A, A′ on C; B′ at D.
∠DAC = ∠B′C′A′ = ∠BCA (△ABC ≅ △A′B′C′)
Alternate angles equal ⇒ AD ∥ BC
∠DCA = ∠B′A′C′ = ∠BAC ⇒ AB ∥ DC
∴ ABCD is a parallelogram.
Common mistakes that cost marks
- Placing the copy without turning it, which does not give equal alternate angles.
- Saying ‘opposite sides look parallel’ without naming the equal alternate angles.
- Matching the wrong angles, e.g. ∠DAC with ∠BAC.
How this can come in the exam
Assertion (A): The area of a triangle is half the area of a parallelogram with the same base and height.
Reason (R): Two congruent copies of a triangle can be fitted together to form a parallelogram with the same base and height.
- Both A and R are true, and R is the correct explanation of A.
- Both A and R are true, but R is not the correct explanation of A.
- A is true but R is false.
- A is false but R is true.
Show answer
(A) Both A and R are true, and R is the correct explanation of A.
Both true, and the parallelogram made from two equal triangles is the reason the triangle has half its area.
Try one yourself
A triangle has base 9 cm and height 4 cm. What is the area of the parallelogram made from two copies of it, and hence the area of the triangle?
Show answer
Parallelogram: 9 × 4 = 36 cm2; triangle = 18 cm2.
More questions like this
- Since ΔABD and ΔACD have equal area, you may wonder — Can we divide ΔABD using straight cuts into two or more pieces that we can then rearrange to exactly cover ΔACD? What do you think? Is it possible?
- Suppose we are given two polygons P and Q with equal area. Will it always be possible to divide one of them using straight cuts into two or more pieces and then rearrange the pieces to exactly cover the other polygon? Try this out for familiar shapes, e.g.,
- Think of various rectangles with perimeter 40 units (the sides do not have to be integers).
- Let us test Heron’s formula against some known cases: an equilateral triangle with side a units.
- Let us test Heron’s formula against some known cases: an isosceles triangle with equal sides a units and base 2b units.