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Dissection of shapes · 3 marks

Suppose we are given two polygons P and Q with equal area. Will it always be possible to divide one of them using straight cuts into two or more pieces and then rearrange the pieces to exactly cover the other polygon? Try this out for familiar shapes, e.g.,

  1. 1. A square and non-square rectangle with equal area,
  2. 2. Two triangles with different shapes but equal area,
  3. 3. A triangle and a square with equal area. Formulate a conjecture of your own about this.
Answer: Yes, every time. (1) 9 × 4 rectangle → 6 × 6 square with one staircase cut. (2) Triangles: each → parallelogram → the same rectangle. (3) Triangle → rectangle → square. Conjecture: any two polygons with equal area can be cut into pieces that rearrange from one into the other (this is a true theorem).

Step-by-step solution

Idea: Use a common ‘middle’ shape. Every triangle can be cut into a rectangle, and any rectangle can be cut into any other rectangle of the same area. Going forward from one shape and backward to the other gives the pieces.

9 × 4 rectangle6 × 6 square→

1. A square and non-square rectangle with equal area,

  1. Yes. Example: a 9 × 4 rectangle and a 6 × 6 square (both area 36). Cut the rectangle along a ‘staircase’ line with steps 3 wide and 2 high. Slide the right piece 3 units left and 2 units up: the two pieces make the 6 × 6 square (see the picture). Only 2 pieces are needed.1 mark
Yes (e.g. 9 × 4 → 6 × 6 with a staircase cut, 2 pieces)

2. Two triangles with different shapes but equal area,

  1. Yes. Cut each triangle along the line joining the midpoints of two sides and turn the top piece half round: each triangle becomes a parallelogram with the same base and half the height. Parallelograms of equal area can be turned into the same rectangle by cutting off a triangle at one end and sliding it to the other. Reversing the steps for the second triangle gives the pieces. (When the triangles have equal bases on one line and a common vertex, like the two halves made by a median, a single cut is enough.)1 mark
Yes (via a parallelogram/rectangle of the same area)

3. A triangle and a square with equal area. Formulate a conjecture of your own about this.

  1. Yes. Triangle → rectangle (base b, height h2) as in 2. Then rectangle → square of the same area, by cutting and sliding (as in 1, or using Baudhāyana’s squaring construction).½ mark
  2. Conjecture: any two polygons with equal area can be cut into a finite number of pieces that rearrange into each other. (Reason: every polygon can be cut into triangles, each triangle into a rectangle, and all the rectangles into strips of one fixed width stacked into one rectangle; equal areas give the same final rectangle.) This is true; it is called the Wallace–Bolyai–Gerwien theorem.½ mark
Yes; conjecture: any two polygons of equal area can be dissected into each other
Yes in all three cases. Conjecture: any two polygons with the same area can be cut into a finite number of pieces and rearranged into each other (the Wallace–Bolyai–Gerwien theorem).

Answer to write in the exam

1.

9 × 4 = 36 = 6 × 6

Staircase cut: steps 3 wide (9 − 6) and 2 high (6 − 4)

Slide right piece 3 left, 2 up

∴ Possible with 2 pieces.

2.

Triangle → parallelogram (cut along midline, rotate top 180°)

Parallelogram → rectangle (cut and slide a triangle)

Equal areas ⇒ same rectangle

∴ Possible.

3.

Triangle → rectangle (b × h2) → square

Conjecture: equal-area polygons can always be cut into finitely many pieces and rearranged into each other.

Common mistakes that cost marks

  • Thinking two shapes need the same perimeter to be rearranged. Only the area must be equal; perimeters can change.
  • Expecting the pieces to be squares or rectangles only. Pieces may be any polygons.
  • Forgetting that pieces may be turned (rotated) as well as slid.

How this can come in the exam

MCQ (1 mark)

A rectangle 8 cm × 2 cm is cut and rearranged without overlap into a square. The side of the square is

  1. 2 cm
  2. 4 cm
  3. 5 cm
  4. 16 cm
Show answer

(B) 4 cm
Area is unchanged: 8 × 2 = 16 cm2, so the side is √16 = 4 cm.

Try one yourself

A 16 × 9 rectangle is to be cut into a square of the same area with a staircase cut. What is the side of the square, and what are the step width and step height?

Show answer

Area 144, so side 12. Step width 16 − 12 = 4, step height 12 − 9 = 3.

More questions like this

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