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Decimal expansions · 5 marks

Convert the following decimal numbers in the form of pq.

  1. (i) 12.6
  2. (ii) 0.0120
  3. (iii) 3.052
  4. (iv) 1.235
  5. (v) 0.23
  6. (vi) 2.05
  7. (vii) 2.125
  8. (viii) 3.125
  9. (ix) 2.1625
Answer: (i) 635 (ii) 3250 (iii) 1511495 (iv) 1223990 (v) 2399 (vi) 3718 (vii) 1913900 (viii) 2813900 (ix) 216239999

Step-by-step solution

Idea: Terminating decimals: write over a power of 10 and simplify. Repeating decimals: let x be the number; multiply by 10m (m = non-repeating digits after the point) and then by 10n more (n = digits in the repeating block); subtract the two equations so the endless tail cancels.

(i) 12.6

  1. One decimal place: 12.6 = 12610 = 635.½ mark
635

(ii) 0.0120

  1. 0.0120 = 0.012 = 121000 = 3250 (divide by 4).½ mark
3250

(iii) 3.052

  1. x = 3.052. 10x = 30.52 and 1000x = 3052.52. Subtract: 990x = 3022, x = 3022990 = 1511495.½ mark
1511495

(iv) 1.235

  1. x = 1.235. 10x = 12.35 and 1000x = 1235.35. Subtract: 990x = 1223, x = 1223990.½ mark
1223990

(v) 0.23

  1. x = 0.23. 100x = 23.23. Subtract: 99x = 23, x = 2399.½ mark
2399

(vi) 2.05

  1. x = 2.05. 10x = 20.5 and 100x = 205.5. Subtract: 90x = 185, x = 18590 = 3718.½ mark
3718

(vii) 2.125

  1. x = 2.125. 100x = 212.5 and 1000x = 2125.5. Subtract: 900x = 1913, x = 1913900.½ mark
1913900

(viii) 3.125

  1. x = 3.125. 100x = 312.5 and 1000x = 3125.5. Subtract: 900x = 2813, x = 2813900.½ mark
2813900

(ix) 2.1625

  1. x = 2.1625: four digits repeat, so multiply by 104: 10000x = 21625.1625.½ mark
  2. Subtract: 9999x = 21623, x = 216239999 (no common factor: 9999 = 32 × 11 × 101, and 21623 is divisible by none of 3, 11, 101).½ mark
216239999
(i) 63/5 (ii) 3/250 (iii) 1511/495 (iv) 1223/990 (v) 23/99 (vi) 37/18 (vii) 1913/900 (viii) 2813/900 (ix) 21623/9999

Check: Divide back: 1511 ÷ 495 = 3.05252…, 1223 ÷ 990 = 1.23535…, 37 ÷ 18 = 2.0555…, 1913 ÷ 900 = 2.12555…, 21623 ÷ 9999 = 2.16251625… ✓.

Answer to write in the exam

(i)

12.6 = 12610

∴ = 635

(ii)

0.0120 = 121000

∴ = 3250

(iii)

x = 3.052

10x = 30.52, 1000x = 3052.52

990x = 3022

∴ x = 3022990 = 1511495

(iv)

x = 1.235

10x = 12.35, 1000x = 1235.35

990x = 1223

∴ x = 1223990

(v)

x = 0.23

100x = 23.23

99x = 23

∴ x = 2399

(vi)

x = 2.05

10x = 20.5, 100x = 205.5

90x = 185

∴ x = 18590 = 3718

(vii)

x = 2.125

100x = 212.5, 1000x = 2125.5

900x = 1913

∴ x = 1913900

(viii)

x = 3.125

100x = 312.5, 1000x = 3125.5

900x = 2813

∴ x = 2813900

(ix)

x = 2.1625

10000x = 21625.1625

9999x = 21623

∴ x = 216239999

Common mistakes that cost marks

  • Putting the bar over the wrong digits: in 3.052 the 0 does not repeat, so it is not 3.052.
  • Multiplying by the wrong power of 10: in (iv) the block 35 has two digits, so the second multiplier is 100, not 10.
  • Treating 0.0120 as 0.12: the zero after the point matters (0.012 = 121000).

How this can come in the exam

MCQ (1 mark)

1.2 in the form pq is

  1. 65
  2. 119
  3. 129
  4. 1210
Show answer

(B) 119
10x − x = 12.2 − 1.2 = 11, so x = 119.

Short answer (3 marks)

Express 0.318 in the form pq.

Show answerx = 0.318; 10x = 3.18 (1 mark); 1000x = 318.18 (1 mark); 990x = 315, x = 315990 = 722 (1 mark).

Try one yourself

Convert 4.06 and 0.132 into the form pq.

Show answer

4.06: 90x = 406 − 40 = 366, x = 6115. 0.132: 999x = 132, x = 44333.

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