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Decimal expansions · 3 marks

Convert 2.4537 into the form pq.

Answer: Let x = 2.4537. 100x = 245.37, 10000x = 24537.37. Subtracting, 9900x = 24292, so x = 242929900 = 60732475.

Step-by-step solution

Idea: ’45’ does not repeat (2 digits) and ’37’ repeats (2 digits). Multiply by 102 for the non-repeating part, then by 102 more for one repeating block, and subtract.

  1. Let x = 2.4537 = 2.453737…½ mark
  2. Two non-repeating digits: multiply by 102 = 100 → 100x = 245.37.½ mark
  3. Two repeating digits: multiply by 100 more → 10000x = 24537.37.½ mark
  4. Subtract: 10000x − 100x = 24537.37 − 245.37 = 24292, so 9900x = 24292.1 mark
  5. x = 242929900 = 60732475 (divide by 4).½ mark
2.4537 = 6073/2475

Check: 6073 ÷ 2475 = 2.4537373… ✓.

Answer to write in the exam

Let x = 2.4537

100x = 245.37 … (1)

10000x = 24537.37 … (2)

(2) − (1): 9900x = 24292

∴ x = 242929900 = 60732475

Common mistakes that cost marks

  • Multiplying by 1000 instead of 10000 for the second step: the block 37 has two digits, so it needs another ×100.
  • Reducing 242929900 only by 2 (121464950); both are divisible by 4.
  • Subtraction slip: 24537 − 245 = 24292.

How this can come in the exam

MCQ (1 mark)

0.123 =

  1. 123999
  2. 122990
  3. 123990
  4. 61500
Show answer

(B) 122990
10x = 1.23, 1000x = 123.23; 990x = 122.

Short answer (3 marks)

Express 3.145 in the form pq.

Show answer10x = 31.45 (1 mark); 1000x = 3145.45 (1 mark); 990x = 3114, x = 3114990 = 17355 (1 mark).

Try one yourself

Convert 0.3612 into the form pq.

Show answer

9900x = 3612 − 36 = 3576, x = 35769900 = 298825.

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