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Area of a circle · 2 marks

As the slices become smaller and smaller, the arcs in the figure (B) become more and more closer to a line. This makes the figure more and more closer to a parallelogram with base = half the circumference (why?) = πr, height = radius r.

(A)(B)
Answer: The slices alternate: half of them point up and half point down. The arcs of the up-pointing slices make the bottom edge and the arcs of the down-pointing slices make the top edge. So each long edge gets half of all the arcs, i.e. half of 2πr = πr.

Step-by-step solution

Idea: The whole circumference 2πr is shared out equally between the top and bottom edges of the rearranged shape.

  1. The arcs of all the slices together make the full circumference, 2πr.1 mark
  2. In the rearrangement the slices point alternately up and down, so exactly half the arcs lie along the bottom and half along the top. Each long side therefore has length 12 × 2πr = πr. The slanting sides are radii, so the height is r, and area = πr × r = πr2.1 mark
Half the slices’ arcs form the base (the other half form the top), so the base is half of 2πr, which is πr.

Answer to write in the exam

Total length of arcs = 2πr

Slices alternate ⇒ half the arcs on the base, half on the top

Base = 12 × 2πr = πr; height = r

∴ Area = πr × r = πr2

Common mistakes that cost marks

  • Taking the base as the full circumference 2πr, which would give area 2πr2.
  • Taking the height as the diameter.

How this can come in the exam

MCQ (1 mark)

A circle of radius 7 cm is cut into many thin slices and rearranged into a near-parallelogram. Its base is about (use π = 227)

  1. 7 cm
  2. 14 cm
  3. 22 cm
  4. 44 cm
Show answer

(C) 22 cm
Base = πr = 227 × 7 = 22 cm.

Try one yourself

A circle of radius 14 cm is cut into slices and rearranged as in the figure. Find the base and height of the near-parallelogram and its area. (Use π = 227.)

Show answer

Base πr = 44 cm, height 14 cm, area 616 cm2.

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