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Linear relationships · 3 marks

A telecom company charges a fixed monthly fee and an additional cost per GB of the internet data used. A student observes that when she used 10 GB, her bill was ₹350. When she used 20 GB, her bill was ₹550. If the monthly bill y depends on the amount of data used, x (in GB), according to the relation y = ax + b, find the values of a and b.

Answer: 350 = 10a + b and 550 = 20a + b give a = 20, b = 150, so y = 20x + 150.

Step-by-step solution

Given: x = 10 GB, y = ₹350; x = 20 GB, y = ₹550; y = ax + b
To find: a and b

Idea: Each observation gives one equation in a and b. Make b the subject of the first and substitute it into the second (substitution).

  1. Substitute the two observations into y = ax + b: 350 = 10a + b and 550 = 20a + b.1 mark
  2. From the first: b = 350 − 10a. Substitute into the second: 550 = 20a + (350 − 10a).½ mark
  3. 550 = 10a + 350 ⇒ 10a = 200 ⇒ a = 20.½ mark
  4. b = 350 − 10 × 20 = 350 − 200 = 150.½ mark
  5. So y = 20x + 150 is the linear relationship between the bill y (₹) and the data x (GB).½ mark
a = 20 and b = 150, so y = 20x + 150.

Check: x = 10: 200 + 150 = 350 ✓. x = 20: 400 + 150 = 550 ✓.

Answer to write in the exam

y = ax + b

350 = 10a + b … (1); 550 = 20a + b … (2)

From (1): b = 350 − 10a

In (2): 550 = 20a + 350 − 10a ⇒ 10a = 200 ⇒ a = 20

b = 350 − 200 = 150

∴ a = 20, b = 150; y = 20x + 150

Common mistakes that cost marks

  • Dividing 350 by 10 to get a = 35. That ignores the fixed fee b.
  • Substituting x and y the wrong way round, writing 10 = 350a + b.
  • Finding a and stopping without finding b.

How this can come in the exam

MCQ (1 mark)

If y = ax + b, y = 9 when x = 2 and y = 21 when x = 6, then a is

  1. 3
  2. 4.5
  3. 12
  4. 2
Show answer

(A) 3
Subtract: 4a = 12, so a = 3 (and b = 3).

Case-based (4 marks)

An electricity board charges a fixed monthly fee plus a rate per unit. A family used 100 units and paid ₹750; next month they used 160 units and paid ₹1110. The bill is y = ax + b for x units.
(i) Write two equations. (ii) Find a. (iii) Find b. (iv) Find the bill for 200 units.

Show answer(i) 750 = 100a + b, 1110 = 160a + b (1 mark). (ii) 60a = 360 ⇒ a = 6 (1 mark). (iii) b = 750 − 600 = 150 (1 mark). (iv) 6 × 200 + 150 = ₹1350 (1 mark).

Try one yourself

A plumber charges a call-out fee plus a rate per hour. A 2-hour job costs ₹700 and a 5-hour job costs ₹1450. Find the rate and the fee.

Show answer

3a = 750 ⇒ a = ₹250 per hour; b = 700 − 500 = ₹200.

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