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Linear relationships · 3 marks

A gym charges a fixed monthly fee and an additional cost per hour for using the badminton court. A student using the gym observed that when she used the badminton court for 10 hours, her bill was ₹800. When she used it for 15 hours, her bill was ₹1100. If the monthly bill y depends on the hours of the use of the badminton court, x, according to the relation y = ax + b, find the values of a and b.

Answer: a = 60, b = 200, so y = 60x + 200 (₹60 per hour, ₹200 fixed fee).

Step-by-step solution

Given: x = 10, y = 800; x = 15, y = 1100
To find: a and b in y = ax + b

Idea: Two observations give two equations in a and b. Substitute b from the first into the second.

  1. 800 = 10a + b … (1) and 1100 = 15a + b … (2).1 mark
  2. From (1), b = 800 − 10a. In (2): 1100 = 15a + 800 − 10a ⇒ 5a = 300 ⇒ a = 60.1 mark
  3. b = 800 − 10 × 60 = 800 − 600 = 200. So y = 60x + 200.1 mark
a = 60 and b = 200 (the bill is y = 60x + 200).

Check: x = 10: 600 + 200 = 800 ✓. x = 15: 900 + 200 = 1100 ✓.

Answer to write in the exam

800 = 10a + b … (1); 1100 = 15a + b … (2)

From (1): b = 800 − 10a

In (2): 1100 = 15a + 800 − 10a ⇒ 5a = 300 ⇒ a = 60

b = 800 − 600 = 200

∴ a = 60, b = 200

Common mistakes that cost marks

  • Taking a = 800 ÷ 10 = 80, ignoring the fixed monthly fee.
  • Writing 5a = 300 as a = 1500.
  • Mixing up a and b in the final answer (saying the fixed fee is ₹60).

How this can come in the exam

MCQ (1 mark)

For the gym above (y = 60x + 200), the bill for 22 hours is

  1. ₹1320
  2. ₹1520
  3. ₹1540
  4. ₹1720
Show answer

(B) ₹1520
60 × 22 + 200 = 1320 + 200 = ₹1520.

Short answer (3 marks)

A cycle rental shop charges a fixed fee plus an hourly rate. 3 hours cost ₹170 and 7 hours cost ₹330. Find the fee and the rate, and the cost for 10 hours.

Show answer4a = 160 ⇒ a = ₹40 per hour (1 mark). b = 170 − 120 = ₹50 (1 mark). 10 hours: 400 + 50 = ₹450 (1 mark).

Try one yourself

A swimming pool charges a fixed fee plus a cost per visit. 4 visits cost ₹380 and 10 visits cost ₹650. Find a and b in y = ax + b.

Show answer

6a = 270 ⇒ a = 45; b = 380 − 180 = 200.

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