A gym charges a fixed monthly fee and an additional cost per hour for using the badminton court. A student using the gym observed that when she used the badminton court for 10 hours, her bill was ₹800. When she used it for 15 hours, her bill was ₹1100. If the monthly bill y depends on the hours of the use of the badminton court, x, according to the relation y = ax + b, find the values of a and b.
Step-by-step solution
To find: a and b in y = ax + b
Idea: Two observations give two equations in a and b. Substitute b from the first into the second.
- 800 = 10a + b … (1) and 1100 = 15a + b … (2).1 mark
- From (1), b = 800 − 10a. In (2): 1100 = 15a + 800 − 10a ⇒ 5a = 300 ⇒ a = 60.1 mark
- b = 800 − 10 × 60 = 800 − 600 = 200. So y = 60x + 200.1 mark
Check: x = 10: 600 + 200 = 800 ✓. x = 15: 900 + 200 = 1100 ✓.
Answer to write in the exam
800 = 10a + b … (1); 1100 = 15a + b … (2)
From (1): b = 800 − 10a
In (2): 1100 = 15a + 800 − 10a ⇒ 5a = 300 ⇒ a = 60
b = 800 − 600 = 200
∴ a = 60, b = 200
Common mistakes that cost marks
- Taking a = 800 ÷ 10 = 80, ignoring the fixed monthly fee.
- Writing 5a = 300 as a = 1500.
- Mixing up a and b in the final answer (saying the fixed fee is ₹60).
How this can come in the exam
For the gym above (y = 60x + 200), the bill for 22 hours is
- ₹1320
- ₹1520
- ₹1540
- ₹1720
Show answer
(B) ₹1520
60 × 22 + 200 = 1320 + 200 = ₹1520.
A cycle rental shop charges a fixed fee plus an hourly rate. 3 hours cost ₹170 and 7 hours cost ₹330. Find the fee and the rate, and the cost for 10 hours.
Show answer
4a = 160 ⇒ a = ₹40 per hour (1 mark). b = 170 − 120 = ₹50 (1 mark). 10 hours: 400 + 50 = ₹450 (1 mark).Try one yourself
A swimming pool charges a fixed fee plus a cost per visit. 4 visits cost ₹380 and 10 visits cost ₹650. Find a and b in y = ax + b.
Show answer
6a = 270 ⇒ a = 45; b = 380 − 180 = 200.
More questions like this
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