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Statistical probability · 3 marks

A teacher mixes a large bag of sweets of different colours and randomly selects a sample of 30 sweets. She counts the number of sweets of each colour:
10 red sweets | 8 green sweets | 7 yellow sweets | 5 blue sweets

  1. (i) Calculate the probability that a randomly picked sweet from the sample is green.
  2. (ii) If there are 600 sweets in total in the large bag, estimate how many are likely to be yellow, based on the sample results.
Answer: (i) P(green) = 830 = 415 ≈ 0.27. (ii) About 730 × 600 = 140 yellow sweets.

Step-by-step solution

Given: Sample of 30 sweets: red 10, green 8, yellow 7, blue 5; Whole bag: 600 sweets

Idea: The sample gives a relative frequency for each colour. Use it as the probability for the sample, and as the estimated share of that colour in the whole bag.

(i) Calculate the probability that a randomly picked sweet from the sample is green.

  1. Total in the sample: 10 + 8 + 7 + 5 = 30. Green sweets: 8.½ mark
  2. P(green) = Number of green sweetsTotal sweets in the sample = 830 = 415 ≈ 0.267 (about 27%).½ mark
P(green) = 415 ≈ 0.27

(ii) If there are 600 sweets in total in the large bag, estimate how many are likely to be yellow, based on the sample results.

  1. In the sample, P(yellow) = 730.½ mark
  2. The sample was picked at random, so the whole bag should have about the same share of yellow sweets.½ mark
  3. Estimated yellow sweets = 730 × 600 = 7 × 20 = 140.1 mark
About 140 yellow sweets
(i) P(green) = 8/30 = 4/15 ≈ 0.27. (ii) About 140 of the 600 sweets are likely to be yellow.

Check: Scale the whole sample up by 600 ÷ 30 = 20: red 200, green 160, yellow 140, blue 100. Total 600 ✓.

Answer to write in the exam

(i)

Total sweets in sample = 10 + 8 + 7 + 5 = 30; green = 8

∴ P(green) = 830 = 415 ≈ 0.27

(ii)

P(yellow) in sample = 730

Estimated yellow sweets = 730 × 600 = 140

∴ About 140 sweets are likely to be yellow

Common mistakes that cost marks

  • Writing 822 for P(green), comparing green with the other colours instead of with the whole sample of 30.
  • In (ii), dividing 600 by 7, or using 7600. The share of yellow (730) must be multiplied by the total, 600.
  • Saying there are exactly 140 yellow sweets. It is an estimate from a sample, so write “about 140”.

How this can come in the exam

Case-based (4 marks)

A fruit seller picks 50 mangoes at random from a crate of 1000 and checks them: 36 are ripe, 10 are unripe and 4 are spoilt.
(a) Find the probability that a mango from the sample is ripe. (1)
(b) Find the probability that a mango from the sample is not spoilt. (1)
(c) Estimate the number of spoilt mangoes in the crate. (2)

Show answer(a) 3650 = 0.72.
(b) (50 − 4)/50 = 4650 = 0.92.
(c) P(spoilt) = 450 = 0.08; estimate = 0.08 × 1000 = 80 mangoes.
MCQ (1 mark)

In a random sample of 20 beads from a jar, 6 are white. The jar has 500 beads. The best estimate of the number of white beads in the jar is

  1. 6
  2. 100
  3. 150
  4. 300
Show answer

(C) 150
620 × 500 = 0.3 × 500 = 150.

Try one yourself

In a random sample of 40 pencils from a box of 400, 12 are blunt. (a) Find the probability that a pencil from the sample is blunt. (b) Estimate the number of blunt pencils in the box.

Show answer

(a) 1240 = 0.3. (b) 0.3 × 400 = 120 pencils.

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