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Experimental probability · 3 marks

Toss a coin 20 times and record the result each time (heads or tails).

  1. (i) How many times did you get heads?
  2. (ii) How many times did you get tails?
  3. (iii) Calculate the experimental probability of getting heads.
  4. (iv) If you toss the coin once more, what is the probability of getting tails?
Answer: Your counts depend on your own tosses. In one sample run: (i) 11 heads (ii) 9 tails (iii) experimental P(heads) = 1120 = 0.55 (iv) P(tails) on the next toss = 12, whatever happened before.

Step-by-step solution

Idea: Experimental probability = Number of times the event occurredTotal number of trials. The next toss is a fresh, independent trial, so its probability is the theoretical 12.

(i) How many times did you get heads?

  1. Record the results in a table. A sample run of 20 tosses:
    H T T H H T H H T H
    T H H T T H T H H T
    (Your own list will be different; use your own counts in each part.)
  2. Count the Hs in your record. In the sample run there are 11 heads.½ mark
11 heads (in the sample run)

(ii) How many times did you get tails?

  1. Tails = 20 − 11 = 9. (Count them to check: there are 9 Ts.)½ mark
9 tails (in the sample run)

(iii) Calculate the experimental probability of getting heads.

  1. Experimental P(heads) = Number of headsTotal number of tosses = 1120½ mark
  2. = 0.55 (55%). With your own counts, use your number of heads20.½ mark
1120 = 0.55 (in the sample run)

(iv) If you toss the coin once more, what is the probability of getting tails?

  1. The next toss is independent of the first 20: the coin has no memory. Heads and tails are still equally likely.½ mark
  2. P(tails) = 12 = 0.5. (The experimental 0.45 for tails in the sample run describes the past 20 tosses; it does not change the chance on the next toss.)½ mark
12
Answers (i)–(iii) depend on your tosses; for the sample run: 11 heads, 9 tails, experimental P(heads) = 11/20 = 0.55. (iv) The probability of tails on the next toss is 1/2.

Check: Your heads and tails must add up to 20, and your experimental P(heads) + P(tails) must add up to 1 (0.55 + 0.45 = 1 ✓). Most people get between 7 and 13 heads in 20 tosses.

Answer to write in the exam

(i)

Sample record: H T T H H T H H T H T H H T T H T H H T

∴ Number of heads = 11

(ii)

Tails = 20 − 11

∴ Number of tails = 9

(iii)

Experimental P(heads) = Number of headsTotal tosses = 1120

∴ Experimental P(heads) = 0.55

(iv)

Each toss is independent; H and T equally likely.

∴ P(tails) = 12

Common mistakes that cost marks

  • Using the experimental value (e.g. 0.45) as the answer to (iv). For the next toss of a fair coin the probability is 12.
  • Dividing by the number of tails instead of by the total 20 in (iii).
  • Expecting exactly 10 heads and thinking the coin is unfair if you get 12. With only 20 tosses, results like 12 and 8 are normal.

How this can come in the exam

MCQ (1 mark)

A coin is tossed 30 times and shows heads 18 times. The experimental probability of getting tails is

  1. 0.4
  2. 0.5
  3. 0.6
  4. 1830
Show answer

(A) 0.4
Tails = 30 − 18 = 12; 1230 = 0.4.

Assertion–Reason (1 mark)

Assertion (A): A coin tossed 40 times showed heads 26 times, so the experimental probability of heads is 0.65.
Reason (R): For a fair coin, the experimental probability of heads is always exactly 0.5.

  1. Both A and R are true, and R is the correct explanation of A.
  2. Both A and R are true, but R is not the correct explanation of A.
  3. A is true but R is false.
  4. A is false but R is true.
Show answer

(C) A is true but R is false.
A is true: 2640 = 0.65. R is false: experimental results vary; only the theoretical probability is exactly 0.5.

Try one yourself

Rahul tossed a coin 25 times and got 14 heads. Find the experimental probability of (a) heads, (b) tails. What is the probability of heads on his 26th toss?

Show answer

(a) 1425 = 0.56. (b) 1125 = 0.44. 26th toss: 12.

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