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Slope and y-intercept · 3 marks

What do all linear functions of the form f(x) = ax + a, a > 0, have in common?

Answer: f(x) = a(x + 1), so every such graph passes through (−1, 0). Also, in each one the slope and the y-intercept are the same number a, and since a > 0 every line rises from left to right (linear growth) and cuts the y-axis above the origin.

Step-by-step solution

Idea: Factorise: ax + a = a(x + 1). Whatever a is, putting x = −1 makes the bracket 0.

xy−4−3−2−112−3−2−112340(−1, 0)y = 3x + 3y = 2x + 2y = x + 1y = ½x + ½
  1. f(x) = ax + a = a(x + 1). At x = −1: f(−1) = a × 0 = 0 for every a. So all the graphs pass through the point (−1, 0): they all cut the x-axis there.1½ marks
  2. In y = ax + b form, the slope is a and the y-intercept is also a: each line cuts the y-axis at (0, a), which is above the origin because a > 0.1 mark
  3. Since the slope a is positive, every such line rises from left to right (linear growth). For example y = x + 1, y = 2x + 2 and y = 3x + 3 all meet at (−1, 0) (see the graph).½ mark
All graphs of f(x) = ax + a (a > 0) pass through the point (−1, 0); in each, the slope equals the y-intercept (both a), and each line rises from left to right.

Check: a = 5: f(−1) = −5 + 5 = 0 ✓. a = 14: f(−1) = −¼ + ¼ = 0 ✓.

Answer to write in the exam

f(x) = ax + a = a(x + 1)

f(−1) = a(0) = 0 for every a

Slope = a > 0, y-intercept = a > 0

∴ All such lines pass through (−1, 0), rise from left to right, and have slope equal to their y-intercept

Common mistakes that cost marks

  • Saying they all pass through the origin. f(0) = a, which is not 0.
  • Saying they are parallel. Different values of a give different slopes.
  • Testing only one or two values of a and not explaining why it works for all, which the factorised form a(x + 1) shows.

How this can come in the exam

MCQ (1 mark)

All lines of the form y = kx − 2k pass through the point

  1. (0, 0)
  2. (2, 0)
  3. (−2, 0)
  4. (0, 2)
Show answer

(B) (2, 0)
y = k(x − 2), which is 0 when x = 2.

Assertion–Reason (1 mark)

Assertion (A): The graphs of y = 4x + 4 and y = 7x + 7 meet on the x-axis.
Reason (R): Both equal a(x + 1), which is 0 at x = −1.

  1. Both A and R are true, and R is the correct explanation of A.
  2. Both A and R are true, but R is not the correct explanation of A.
  3. A is true but R is false.
  4. A is false but R is true.
Show answer

(A) Both A and R are true, and R is the correct explanation of A.
Both are 0 at x = −1, so both pass through (−1, 0) on the x-axis. R explains A.

Try one yourself

What do all lines y = ax + 3a (a > 0) have in common?

Show answer

y = a(x + 3), so all pass through (−3, 0); each rises to the right, and its y-intercept 3a is 3 times its slope.

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