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Volume of a cuboid · 3 marks

The surface areas of the three faces of a cuboid that meet at one of the corners of the cuboid are 6 cm2, 15 cm2, and 10 cm2 respectively. What is the volume of the cuboid?

Answer: (lw)(wh)(hl) = (lwh)2 = 6 × 15 × 10 = 900, so volume = √900 = 30 cm3 (the cuboid is 2 cm × 3 cm × 5 cm).

Step-by-step solution

Given: Three faces at a corner: 6 cm2, 15 cm2, 10 cm2
To find: Volume of the cuboid

Idea: The three faces at a corner are lw, wh and hl. Their product contains each edge twice, so it equals (volume)2.

  1. Let the edges be l, w, h. The three faces meeting at a corner have areas lw = 6, wh = 15, hl = 10.1 mark
  2. Multiply: (lw)(wh)(hl) = l2w2h2 = (lwh)2 = 6 × 15 × 10 = 900.1 mark
  3. Volume = lwh = √900 = 30 cm3 (volume is positive).1 mark
Volume = 30 cm³.

Check: Edges: h = 30 ÷ 6 = 5, l = 30 ÷ 15 = 2, w = 30 ÷ 10 = 3. Faces 2 × 3 = 6, 3 × 5 = 15, 5 × 2 = 10 ✓, and 2 × 3 × 5 = 30 ✓.

Answer to write in the exam

Let lw = 6, wh = 15, hl = 10

(lw)(wh)(hl) = (lwh)2

(lwh)2 = 6 × 15 × 10 = 900

∴ Volume = lwh = 30 cm3

Common mistakes that cost marks

  • Adding the areas (31) or multiplying them (900) and calling that the volume. The product is the square of the volume.
  • Taking the cube root of 900 instead of the square root.

How this can come in the exam

MCQ (1 mark)

The three faces of a cuboid meeting at a corner have areas 12 cm2, 20 cm2 and 15 cm2. Its volume is

  1. 47 cm3
  2. 3600 cm3
  3. 60 cm3
  4. 120 cm3
Show answer

(C) 60 cm3
√(12 × 20 × 15) = √3600 = 60 cm3 (edges 3, 4, 5).

Try one yourself

Three faces of a cuboid meeting at a corner have areas 8 cm2, 18 cm2 and 36 cm2. Find its volume.

Show answer

√(8 × 18 × 36) = √5184 = 72 cm3 (edges 2, 4, 9).

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