The radius of a sphere is increased by 10%. Show that the volume increases by approximately 33.1%.
Answer: New radius 1.1r ⇒ new volume = (1.1)3 × old = 1.331 × old, an increase of 0.331 = 33.1%.
Step-by-step solution
Idea: Volume depends on r3, so multiplying the radius by 1.1 multiplies the volume by 1.13.
- Old volume = 43πr3. New radius = r + 10% of r = 1.1r.½ mark
- New volume = 43π(1.1r)3 = 1.331 × 43πr3 (since 1.1 × 1.1 × 1.1 = 1.331).1 mark
- Increase = (1.331 − 1) × old = 0.331 × old, i.e. 33.1%. Shown.½ mark
New volume = 1.331 × old volume, so the volume increases by 33.1%.
Check: r = 10: volume ∝ 1000; r = 11: volume ∝ 1331; (1331 − 1000) ÷ 1000 = 33.1% ✓.
Answer to write in the exam
New radius = 1.1r
New volume = 43π(1.1r)3 = 1.331 × 43πr3
Increase = (1.331 − 1) × 100% = 33.1%
∴ The volume increases by about 33.1%
Common mistakes that cost marks
- Answering 10% or 30% (3 × 10%).
- Working out 1.13 as 1.33 and calling the increase 33% without the extra decimal.
How this can come in the exam
MCQ (1 mark)
If the radius of a sphere is increased by 10%, its surface area increases by
- 10%
- 20%
- 21%
- 33.1%
Show answer
(C) 21%
1.12 = 1.21: an increase of 21%.
Try one yourself
The radius of a sphere is decreased by 10%. By what percentage does its volume decrease?
Show answer
0.93 = 0.729: decrease of 27.1%.
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