The figure depicts a 400 m athletics track. You can see two straight sections of length 84.39 m each, and two curved portions, which are semicircles with a common centre (points A and B); the innermost semicircle on each side has radius 36.5 m. The width of each lane is 1.22 m. Let an athlete make one complete circuit of the track. What is the total distance she runs?
Step-by-step solution
To find: Total distance for one complete circuit
Idea: One lap = two straights + two semicircles. Two semicircles of the same radius make one full circle, so use 2πr with the radius of her actual path, 36.5 + 0.3 = 36.8 m.
- Straights: 2 × 84.39 = 168.78 m.½ mark
- Her path on each bend is 0.3 m outside the inner border, so its radius is 36.5 + 0.3 = 36.8 m.½ mark
- The two semicircles make one full circle: 2 × π × 36.8 = 2 × 3.1416 × 36.8 = 231.22 m.1 mark
- Total = 168.78 + 231.22 = 400 m.1 mark
Check: 2 × 3.1416 × 36.8 = 231.222 m, and 168.78 + 231.22 = 400.00 ✓. This is exactly why the track is called a 400 m track.
Answer to write in the exam
Straights = 2 × 84.39 = 168.78 m
Radius of path on bends = 36.5 + 0.3 = 36.8 m
Two semicircles = 2πr = 2 × 3.1416 × 36.8 = 231.22 m
∴ Total distance = 168.78 + 231.22 = 400 m
Common mistakes that cost marks
- Using radius 36.5 m: that gives about 398.1 m. A runner cannot run exactly on the border line.
- Counting each semicircle as a full circle, which gives about 631 m.
- Adding only one straight.
How this can come in the exam
A track has two straights of 100 m and two semicircular ends. A runner’s path on the ends has radius 31.5 m. How far does she run in one lap? (Use π = 227.)
Show answer
Bends: 2 × 227 × 31.5 = 198 m (1 mark). Lap = 200 + 198 = 398 m (1 mark).Try one yourself
On the track described above, a runner keeps 0.3 m outside the inner line of lane 2 (radius 36.5 + 1.22 + 0.3 = 38.02 m on the bends). How far does she run in one lap? (Use π = 3.1416.)
Show answer
168.78 + 2 × 3.1416 × 38.02 = 168.78 + 238.89 ≈ 407.67 m.
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