The cost of one paratha and 2 bowls of dahi is ₹90. Also, the cost of 2 parathas and 7 bowls of dahi is ₹260. Can you figure out the cost of one paratha and one bowl of dahi and explain your reasoning?
Step-by-step solution
To find: Cost of one paratha and of one bowl of dahi
Idea: Make the number of parathas the same in both orders by doubling the first one. Then the only difference between the orders is extra dahi, and the extra cost tells us its price.
- Let one paratha cost ₹p and one bowl of dahi ₹d. Then p + 2d = 90 … (1) and 2p + 7d = 260 … (2).1 mark
- Double (1): 2p + 4d = 180 … (3). That is, 2 parathas and 4 dahi would cost ₹180.½ mark
- Subtract (3) from (2): (2) has the same 2 parathas but 3 more bowls of dahi and costs 260 − 180 = ₹80 more. So 3d = 80, d = 803 ≈ ₹26.67.1 mark
- From (1): p = 90 − 2 × 803 = 90 − 1603 = 1103 ≈ ₹36.67. These are not whole rupees, but they fit both bills exactly.½ mark
Check: (1): 1103 + 1603 = 2703 = 90 ✓. (2): 2203 + 5603 = 7803 = 260 ✓.
Answer to write in the exam
Let paratha = ₹p, dahi = ₹d
p + 2d = 90 … (1); 2p + 7d = 260 … (2)
(1) × 2: 2p + 4d = 180 … (3)
(2) − (3): 3d = 80 ⇒ d = 803 ≈ 26.67
p = 90 − 1603 = 1103 ≈ 36.67
∴ Paratha ≈ ₹36.67, dahi ≈ ₹26.67
Common mistakes that cost marks
- Subtracting the two bills straight away (260 − 90 = 170) and calling that one item’s price. The orders differ in both items, so first make one item match.
- Rounding d to ₹27 early and then getting p = ₹36; the check then fails (36 + 54 = 90 but 72 + 189 = 261).
- Assuming the answer must be whole rupees and giving up when it is not.
How this can come in the exam
At a canteen, 1 samosa and 3 cups of tea cost ₹55, while 2 samosas and 1 cup of tea cost ₹40.
(i) Write the two equations. (ii) Find the cost of one samosa and one cup of tea. (iii) What do 3 samosas and 2 cups of tea cost?
Show answer
(i) s + 3t = 55, 2s + t = 40 (1 mark). (ii) Double the first: 2s + 6t = 110; subtract the second: 5t = 70 ⇒ t = 14; s = 55 − 42 = 13 (2 marks). (iii) 39 + 28 = ₹67 (1 mark).Try one yourself
2 pens and 3 notebooks cost ₹110; 4 pens and 7 notebooks cost ₹240. Find each price.
Show answer
Double the first: 4 pens + 6 notebooks = ₹220; so 1 notebook = 240 − 220 = ₹20; pen = (110 − 60) ÷ 2 = ₹25.
More questions like this
- Rakesh’s puzzle: “I have thought of two numbers”, he said. “Their sum is 25 and their difference is 11”.
We can also solve this using a pair of linear equations. - Consider another situation. A science exhibition charges an entry fee that is different for adults and children. Here are the amount paid by two different groups.
Group A: 2 adult tickets and 3 child tickets for ₹600
Group B: 3 adult tickets and 2 child tickets for ₹700
How much do individual adult and child tickets cost?
If the cost of one adult ticket is ₹x and one child ticket is ₹y, then: 2x + 3y = 600, 3x + 2y = 700.
This gives us another pair of linear equations in two variables. A solution to these equations will give us the answer that we seek. Can you see why? - Given below are some everyday situations. Construct a pair of linear equations in two variables for each situation:
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- In a sports meet, tickets for adults cost ₹150 each and tickets for children cost ₹100 each. A total of 200 people attended the meet, and the total amount collected from ticket sales was ₹25,000. (Let the number of adult tickets sold be x and the number of children’s tickets sold be y.) Frame a pair of linear equations in x and y to represent this situation.
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