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Linear growth and decay · 2 marks

The cost of a journey is given by the linear function C(d) = 100 + 60d, where C indicates total cost in rupees and d the distance travelled in km.
What is the cost for travelling 15 km? For how many kilometres will the cost of the journey be ₹700?

Answer: C(15) = 100 + 900 = ₹1000. 100 + 60d = 700 gives d = 10 km.

Step-by-step solution

Given: C(d) = 100 + 60d

Idea: The first part is an input (find the output). The second part gives the output; set up the equation and solve for the input.

  1. C(15) = 100 + 60 × 15 = 100 + 900 = ₹1000.1 mark
  2. 100 + 60d = 700 ⇒ 60d = 600 ⇒ d = 10 km.1 mark
The cost for 15 km is ₹1000, and the cost is ₹700 for a journey of 10 km.

Check: C(10) = 100 + 600 = 700 ✓.

Answer to write in the exam

C(15) = 100 + 60(15) = 100 + 900 = 1000

100 + 60d = 700 ⇒ 60d = 600 ⇒ d = 10

∴ Cost for 15 km = ₹1000; the cost is ₹700 for 10 km

Common mistakes that cost marks

  • Working out 100 + 60 × 15 as 160 × 15 = 2400. Multiply first: 60 × 15 = 900, then add 100.
  • Solving 100 + 60d = 700 as d = 700 ÷ 60 ≈ 11.7, forgetting the fixed ₹100.
  • Mixing up the two questions: giving a distance for the first and a cost for the second.

How this can come in the exam

MCQ (1 mark)

For C(d) = 150 + 40d, the distance for which the cost is ₹550 is

  1. 13.75 km
  2. 10 km
  3. 17.5 km
  4. 8 km
Show answer

(B) 10 km
40d = 400 ⇒ d = 10.

Short answer (2 marks)

A cab company charges C(d) = 70 + 22d rupees. Find the cost for 25 km and the distance for which the cost is ₹532.

Show answer70 + 550 = ₹620 (1 mark). 22d = 462 ⇒ d = 21 km (1 mark).

Try one yourself

Using C(d) = 100 + 60d, find the cost for 8 km and the distance for which the cost is ₹1300.

Show answer

₹580; 60d = 1200 ⇒ d = 20 km.

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