The cost of a journey is given by the linear function C(d) = 100 + 60d, where C indicates total cost in rupees and d the distance travelled in km.
What is the cost for travelling 15 km? For how many kilometres will the cost of the journey be ₹700?
Answer: C(15) = 100 + 900 = ₹1000. 100 + 60d = 700 gives d = 10 km.
Step-by-step solution
Given: C(d) = 100 + 60d
Idea: The first part is an input (find the output). The second part gives the output; set up the equation and solve for the input.
- C(15) = 100 + 60 × 15 = 100 + 900 = ₹1000.1 mark
- 100 + 60d = 700 ⇒ 60d = 600 ⇒ d = 10 km.1 mark
The cost for 15 km is ₹1000, and the cost is ₹700 for a journey of 10 km.
Check: C(10) = 100 + 600 = 700 ✓.
Answer to write in the exam
C(15) = 100 + 60(15) = 100 + 900 = 1000
100 + 60d = 700 ⇒ 60d = 600 ⇒ d = 10
∴ Cost for 15 km = ₹1000; the cost is ₹700 for 10 km
Common mistakes that cost marks
- Working out 100 + 60 × 15 as 160 × 15 = 2400. Multiply first: 60 × 15 = 900, then add 100.
- Solving 100 + 60d = 700 as d = 700 ÷ 60 ≈ 11.7, forgetting the fixed ₹100.
- Mixing up the two questions: giving a distance for the first and a cost for the second.
How this can come in the exam
MCQ (1 mark)
For C(d) = 150 + 40d, the distance for which the cost is ₹550 is
- 13.75 km
- 10 km
- 17.5 km
- 8 km
Show answer
(B) 10 km
40d = 400 ⇒ d = 10.
Short answer (2 marks)
A cab company charges C(d) = 70 + 22d rupees. Find the cost for 25 km and the distance for which the cost is ₹532.
Show answer
70 + 550 = ₹620 (1 mark). 22d = 462 ⇒ d = 21 km (1 mark).Try one yourself
Using C(d) = 100 + 60d, find the cost for 8 km and the distance for which the cost is ₹1300.
Show answer
₹580; 60d = 1200 ⇒ d = 20 km.
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