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Word problems on pairs of equations · 3 marks

The age of a father is equal to the sum of the ages of his four children. After 20 years, the sum of the ages of the children will be twice the age of the father. Find the age of the father.

Answer: The father is 40 years old.

Step-by-step solution

Idea: Let the father be x years and the children’s total y years. In 20 years each of the four children gains 20 years, so their total gains 4 × 20 = 80.

  1. Now: x = y … (1).½ mark
  2. After 20 years: father x + 20; children’s total y + 4 × 20 = y + 80. So y + 80 = 2(x + 20) ⇒ y − 2x = −40 … (2).1½ marks
  3. (1) in (2): x − 2x = −40 ⇒ x = 40. The father is 40 years old.1 mark
The father is 40 years old.

Check: Now: father 40, children’s total 40 ✓. In 20 years: father 60, children 40 + 80 = 120 = 2 × 60 ✓.

Answer to write in the exam

Let father = x years, sum of children’s ages = y years

x = y … (1)

y + 80 = 2(x + 20) … (2)

(1) in (2): x + 80 = 2x + 40 ⇒ x = 40

∴ Father’s age = 40 years

Common mistakes that cost marks

  • Adding only 20 to the children’s total instead of 4 × 20 = 80.
  • Writing 2(y + 80) = x + 20 (doubling the wrong side).

How this can come in the exam

MCQ (1 mark)

A mother’s age equals the sum of her 3 children’s ages. In 15 years the children’s total will be 1½ times her age. Her present age is

  1. 30
  2. 45
  3. 60
  4. 36
Show answer

(B) 45
x + 45 = 1.5(x + 15) ⇒ 0.5x = 22.5 ⇒ x = 45.

Try one yourself

A man’s age equals the sum of the ages of his five children. After 12 years, the children’s total age will be twice his age. Find his age.

Show answer

x + 60 = 2(x + 12) ⇒ x = 36 years (check: 48 and 96 = 2 × 48).

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