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Number line · 2 marks

The absolute value of a rational number x, written as |x|, represents its distance from 0 on the number line. |53| = 53, |−53| is also equal to 53 and |0| = 0.

Answer: |53| = 53, |−53| = 53 and |0| = 0, because 53 and −53 are both 53 units from 0, and 0 is at 0 itself.

Step-by-step solution

Idea: Absolute value = distance from 0. A distance is never negative, and a number and its negative sit at the same distance on opposite sides of 0.

−2−101253−53both points are 5/3 from 0
  1. 53 = 123 lies 53 units to the right of 0, so |53| = 53.½ mark
  2. −53 lies 53 units to the left of 0. The direction does not matter for a distance, so |−53| = 53.½ mark
  3. 0 is at distance 0 from itself, so |0| = 0.½ mark
  4. So the absolute value of a positive number is the number itself, of a negative number is its positive value, and |x| ≥ 0 always.½ mark
|5/3| = 5/3, |−5/3| = 5/3 and |0| = 0.

Check: Distance between 5/3 and −5/3 is 53 + 53 = 103 = |53 − (−53)| ✓.

Answer to write in the exam

|x| = distance of x from 0

|53| = 53 (53 units right of 0)

|−53| = 53 (53 units left of 0)

|0| = 0

∴ |53| = |−53| = 53 and |0| = 0

Common mistakes that cost marks

  • Writing |−53| = −53. An absolute value is a distance and is never negative.
  • Thinking |x| just ‘removes the minus sign’ from the symbol; |−(−2)| = |2| = 2, so simplify inside first.
  • Writing |0| = 1 or saying |0| is undefined.

How this can come in the exam

MCQ (1 mark)

|−38| + |18| =

  1. −14
  2. 14
  3. 12
  4. −12
Show answer

(C) 12
38 + 18 = 48 = 12.

Short answer (2 marks)

Find the distance between −72 and 34 on the number line.

Show answerDistance = |34 − (−72)| (1 mark) = |34 + 144| = 174 (1 mark).

Try one yourself

Find |−94|, |27| and |−6|.

Show answer

94, 27 and 6.

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