Suppose we have to calculate 292. We can express this as (30 − 1)2.
Answer: 292 = (30 − 1)2 = 900 − 60 + 1 = 841
Step-by-step solution
Given: 29 = 30 − 1
To find: 292
To find: 292
Idea: 29 is just below the round number 30, so write it as a difference and use (a − b)2 = a2 − 2ab + b2.
- 29 = 30 − 1, so a = 30, b = 1.½ mark
- 292 = (30 − 1)2 = 302 − 2 × 30 × 1 + 12½ mark
- = 900 − 60 + 1½ mark
- = 841½ mark
29² = 841.
Check: 29 × 29 = 29 × 30 − 29 = 870 − 29 = 841 ✓.
Answer to write in the exam
292 = (30 − 1)2 = 302 − 2 × 30 × 1 + 12 [(a − b)2 = a2 − 2ab + b2]
= 900 − 60 + 1
∴ 292 = 841
Common mistakes that cost marks
- Writing (30 − 1)2 = 900 − 1 = 899. The middle term −2 × 30 × 1 = −60 is missing.
- Writing the last term as −1. It is +12 = +1.
- Using 29 = 20 + 9 with (a + b)2. Correct, but the arithmetic (400 + 360 + 81) is longer than with 30 − 1.
How this can come in the exam
MCQ (1 mark)
Using (a − b)2, the value of 992 is
- 9801
- 9810
- 9999
- 9891
Show answer
(A) 9801
(100 − 1)2 = 10000 − 200 + 1 = 9801.
Short answer (2 marks)
Find 482 using a suitable identity.
Show answer
482 = (50 − 2)2 = 502 − 2 × 50 × 2 + 22 (1 mark) = 2500 − 200 + 4 = 2304 (1 mark).Try one yourself
Find 592 using (a − b)2 = a2 − 2ab + b2.
Show answer
(60 − 1)2 = 3600 − 120 + 1 = 3481.
More questions like this
- Factor completely:
- Find the values of the following using the identity (a − b)2 = a2 − 2ab + b2.
- What will happen if we want to find the square of the sum of three numbers a, b and c, that is, (a + b + c)2?
- Label the squares and rectangles in the figure so that it represents the identity (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca.
- Let us use this identity to find the square of a number, say 119: