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Algebraic identities · 2 marks

Suppose we have to calculate 292. We can express this as (30 − 1)2.

Answer: 292 = (30 − 1)2 = 900 − 60 + 1 = 841

Step-by-step solution

Given: 29 = 30 − 1
To find: 292

Idea: 29 is just below the round number 30, so write it as a difference and use (a − b)2 = a2 − 2ab + b2.

  1. 29 = 30 − 1, so a = 30, b = 1.½ mark
  2. 292 = (30 − 1)2 = 302 − 2 × 30 × 1 + 12½ mark
  3. = 900 − 60 + 1½ mark
  4. = 841½ mark
29² = 841.

Check: 29 × 29 = 29 × 30 − 29 = 870 − 29 = 841 ✓.

Answer to write in the exam

292 = (30 − 1)2 = 302 − 2 × 30 × 1 + 12 [(a − b)2 = a2 − 2ab + b2]

= 900 − 60 + 1

∴ 292 = 841

Common mistakes that cost marks

  • Writing (30 − 1)2 = 900 − 1 = 899. The middle term −2 × 30 × 1 = −60 is missing.
  • Writing the last term as −1. It is +12 = +1.
  • Using 29 = 20 + 9 with (a + b)2. Correct, but the arithmetic (400 + 360 + 81) is longer than with 30 − 1.

How this can come in the exam

MCQ (1 mark)

Using (a − b)2, the value of 992 is

  1. 9801
  2. 9810
  3. 9999
  4. 9891
Show answer

(A) 9801
(100 − 1)2 = 10000 − 200 + 1 = 9801.

Short answer (2 marks)

Find 482 using a suitable identity.

Show answer482 = (50 − 2)2 = 502 − 2 × 50 × 2 + 22 (1 mark) = 2500 − 200 + 4 = 2304 (1 mark).

Try one yourself

Find 592 using (a − b)2 = a2 − 2ab + b2.

Show answer

(60 − 1)2 = 3600 − 120 + 1 = 3481.

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