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Graphical method · 4 marks

Solve the following system of equations graphically:
2x + y = 6, 2x − y − 2 = 0.

Answer: The lines meet at (2, 2): x = 2, y = 2.

Step-by-step solution

Idea: Draw each line from a table of two or three points; the solution is the point common to both lines.

xy−11234−3−2−112345602x + y = 62x − y = 2(3, 0)(0, −2)(1, 0)(2, 2)
  1. 2x + y = 6:
    x013
    y640
    1 mark
  2. 2x − y − 2 = 0, i.e. y = 2x − 2:
    x013
    y−204
    1 mark
  3. Plot both sets of points and draw the two lines (see the graph).1 mark
  4. They intersect at (2, 2). So x = 2, y = 2.1 mark
x = 2, y = 2.

Check: 2(2) + 2 = 6 ✓; 2(2) − 2 − 2 = 0 ✓.

Answer to write in the exam

2x + y = 6:

x013
y640

2x − y − 2 = 0:

x013
y−204

Plotting, the lines intersect at (2, 2)

∴ x = 2, y = 2

Common mistakes that cost marks

  • Rewriting 2x − y − 2 = 0 as y = −2x + 2 (sign error).
  • Reading the crossing point as (2, 1) from a rough sketch.

How this can come in the exam

MCQ (1 mark)

The graphs of x + y = 6 and x − y = 2 intersect at

  1. (2, 4)
  2. (4, 2)
  3. (3, 3)
  4. (6, 0)
Show answer

(B) (4, 2)
Adding: 2x = 8 ⇒ x = 4, y = 2.

Try one yourself

Solve graphically: x + 2y = 4 and x − y = 1.

Show answer

Points (0, 2), (4, 0) and (1, 0), (3, 2): the lines meet at (2, 1).

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