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Area of a rhombus · 2 marks

One diagonal of a rhombus is twice as long as the other diagonal. If the rhombus has area 128 cm2, find the length of the shorter diagonal.

Answer: Area = 12 × d × 2d = d2 = 128, so d = √128 = 8√2 ≈ 11.31 cm.

Step-by-step solution

Given: Diagonals d and 2d; Area = 128 cm2
To find: Shorter diagonal d

Idea: The diagonals of a rhombus cut each other at right angles, so its area is half the product of the diagonals.

  1. Let the shorter diagonal be d; the longer is 2d. Area = 12 × d × 2d = d2.1 mark
  2. d2 = 128 ⇒ d = √128 = √(64 × 2) = 8√2 ≈ 11.31 cm.1 mark
The shorter diagonal is 8√2 cm ≈ 11.31 cm.

Check: Diagonals 8√2 and 16√2: 12 × 8√2 × 16√2 = 12 × 256 = 128 ✓.

Answer to write in the exam

Area = 12 × d1 × d2 = 12 × d × 2d = d2

d2 = 128

∴ d = 8√2 cm ≈ 11.31 cm

Common mistakes that cost marks

  • Writing area = d × 2d (forgetting the 12), giving d = 8.
  • Giving the longer diagonal (16√2) instead of the shorter one.

How this can come in the exam

MCQ (1 mark)

The diagonals of a rhombus are 10 cm and 24 cm. Its area is

  1. 120 cm2
  2. 240 cm2
  3. 60 cm2
  4. 34 cm2
Show answer

(A) 120 cm2
12 × 10 × 24 = 120 cm2.

Try one yourself

One diagonal of a rhombus is three times the other, and its area is 150 cm2. Find the diagonals.

Show answer

12 × d × 3d = 150 ⇒ d2 = 100 ⇒ 10 cm and 30 cm.

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