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Factors and perfect squares · 2 marks

For example, if the number of such pairs is two — say (f, f) and (g, g) — what can we say about the number of factors?

Answer: The number of factors would be even: the other factors come in pairs of two different numbers (an even count), and f and g add 2 more. (This can never actually happen, since f × f = g × g forces f = g.)

Step-by-step solution

Given: ‘Such pairs’ are factor–partner pairs of n in which the same number repeats

Idea: Count factors pair by pair: a pair of two different numbers gives 2 factors, a repeated pair gives only 1.

  1. Every factor that is not in a repeated pair has a partner different from itself, so these factors come in twos: an even number of them, say 2k.½ mark
  2. Each repeated pair gives only one factor. The two repeated pairs (f, f) and (g, g) give 2 factors: f and g.½ mark
  3. Total = 2k + 2 = 2(k + 1), an even number.½ mark
  4. That is why (ii) alone cannot give (i). In fact this case never happens: f × f = g × g with f, g positive means f = g, so a number has at most one repeated pair.½ mark
With two repeated pairs the number of factors would be even (2k + 2). Since a number can have at most one repeated pair, this case never actually occurs.

Answer to write in the exam

Factors not in repeated pairs come in pairs of two different numbers: 2k factors

Repeated pairs (f, f), (g, g) add 2 factors: f, g

Total = 2k + 2 = 2(k + 1)

∴ The number of factors would be even.

Common mistakes that cost marks

  • Counting a repeated pair as two factors. (f, f) gives only one factor, f.
  • Answering ‘odd’ because the number is a square. The question asks about the (impossible) case of two repeated pairs.

How this can come in the exam

MCQ (1 mark)

A number has factor–partner pairs (1, 400), (2, 200), (4, 100), (5, 80), (8, 50), (10, 40), (16, 25), (20, 20). How many factors does it have?

  1. 8
  2. 15
  3. 16
  4. 17
Show answer

(B) 15
Seven pairs of different numbers give 14 factors, and (20, 20) gives one more: 15.

Short answer (2 marks)

Explain why no positive integer can have two different factor–partner pairs (f, f) and (g, g).

Show answerBoth pairs multiply to the same number, so f × f = g × g (1 mark). If f < g then f × f < g × g, and if f > g then f × f > g × g; so f = g and the pairs are the same (1 mark).

Try one yourself

225 has factor–partner pairs (1, 225), (3, 75), (5, 45), (9, 25), (15, 15). How many factors does it have, and why is the number odd?

Show answer

Four pairs of different numbers give 8 factors and (15, 15) gives one more: 9 factors. It is odd because exactly one pair repeats.

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