Find the degrees of the following polynomials:
- (i) 2x2 − 5x + 3
- (ii) y3 + 2y − 1
- (iii) −9
- (iv) 4z − 3
Step-by-step solution
Idea: The degree of a polynomial in one variable is the highest power of the variable that appears (with a non-zero coefficient). A constant like −9 can be written −9x0, so its degree is 0.
(i) 2x2 − 5x + 3
- Powers of x present: x2, x1 (in −5x) and x0 (in the constant 3). The highest is 2.½ mark
(ii) y3 + 2y − 1
- Powers of y present: 3, 1 and 0. The highest is 3. (There is no y2 term, but that does not matter: we only need the highest power.)½ mark
(iii) −9
- −9 has no variable. It can be written as −9x0, because x0 = 1. So the highest power is 0.½ mark
(iv) 4z − 3
- 4z = 4z1, and the constant −3 = −3z0. The highest power of z is 1.½ mark
Answer to write in the exam
(i)
Highest power of x = 2
∴ Degree = 2
(ii)
Highest power of y = 3
∴ Degree = 3
(iii)
−9 = −9x0
∴ Degree = 0
(iv)
Highest power of z = 1
∴ Degree = 1
Common mistakes that cost marks
- Giving the degree of −9 as 1 or saying it has no degree. A non-zero constant has degree 0.
- Adding the powers (for example 3 + 1 = 4 for y3 + 2y − 1). The degree is the highest power, not the sum.
- Reading the coefficient as the degree, for example saying 4z − 3 has degree 4. The 4 is a coefficient; the power of z is 1.
How this can come in the exam
The degree of the polynomial 7 − 3p + 5p4 − p2 is
- 7
- 2
- 4
- 5
Show answer
(C) 4
The highest power of p is 4 (in 5p4).
Assertion (A): The polynomial 12 has degree 0.
Reason (R): A non-zero constant c can be written as cx0.
- Both A and R are true, and R is the correct explanation of A.
- Both A and R are true, but R is not the correct explanation of A.
- A is true but R is false.
- A is false but R is true.
Show answer
(A) Both A and R are true, and R is the correct explanation of A.
12 = 12x0, so the highest power of x is 0. R is the reason A is true.
Try one yourself
Find the degrees of (a) 6t2 + t5 − 1 (b) 8 − 2m (c) 15.
Show answer
(a) 5 (b) 1 (c) 0.
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