Find the 10th and nth terms of the GP: 5, 25, 125, … .
Answer: tn = 5 × 5n−1 = 5n; t10 = 510 = 9765625.
Step-by-step solution
Idea: a = 5 and r = 255 = 5. Use tn = arn−1.
- a = 5, r = 255 = 5.½ mark
- tn = 5 × 5n−1 = 5n.½ mark
- t10 = 510 = 9765625.1 mark
nth term = 5ⁿ; 10th term = 5¹⁰ = 9765625.
Check: n = 3: 5³ = 125 ✓.
Answer to write in the exam
a = 5, r = 255 = 5
tn = arn−1 = 5 × 5n−1 = 5n
t10 = 510 = 9765625
∴ t10 = 9765625, tn = 5n
Common mistakes that cost marks
- Writing the nth term as 5n−1 (which gives 1 for the first term).
- Computing 510 as 5 × 10 = 50.
- Writing 5 × 5n−1 = 25n−1. Multiply powers of the same base by adding exponents: 51 × 5n−1 = 5n.
How this can come in the exam
MCQ (1 mark)
The nth term of the GP 4, 16, 64, … is
- 4n
- 4n−1
- 16n−1
- 4n
Show answer
(A) 4n
4 × 4n−1 = 4n.
Try one yourself
Find the 8th and nth terms of the GP 3, 6, 12, …
Show answer
nth term = 3 × 2n−1; 8th term = 3 × 128 = 384.
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