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Tree diagrams · 3 marks

Experiment: Toss a fair coin two times.

Answer: The tree diagram shows 4 possible outcomes: S = {HH, HT, TH, TT}. Each has probability 14, so P(HH) = 14 = 0.25 or 25%.

Step-by-step solution

Idea: A tree diagram lists all outcomes of a multi-step experiment: draw branches for the first toss, then from each of those draw branches for the second toss. Each path from start to end is one complete outcome.

First tossSecond tossOutcome1/2H1/2HHH1/2THT1/2T1/2HTH1/2TTT
  1. First toss: from a single starting point, draw a line to each possible outcome of the first toss, H and T. Each branch has probability 12.½ mark
  2. Second toss: from each of these outcomes draw two lines, to H and to T, again each with probability 12.½ mark
  3. Follow each path from start to end: H then H, H then T, T then H, T then T. Yes, the tree diagram shows 4 possible outcomes. Hence the sample space S = {HH, HT, TH, TT}.1 mark
  4. The 4 outcomes are equally likely. The event ‘getting Heads twice’ is the single outcome HH, so
    Probability of HH = Number of favourable outcomesNumber of possible outcomes = 14 = 0.25 or 25%.1 mark
Sample space S = {HH, HT, TH, TT} (4 outcomes, each with probability 1/4). Probability of HH = 1/4 = 0.25 or 25%.

Check: Number of outcomes = 2 (first toss) × 2 (second toss) = 4 ✓. Also 12 × 12 = 14 along the HH path ✓.

Answer to write in the exam

First toss: H, T (12 each); second toss from each: H, T (12 each)

Paths: HH, HT, TH, TT, so 4 possible outcomes

S = {HH, HT, TH, TT}

∴ P(HH) = 14 = 0.25 or 25%

Common mistakes that cost marks

  • Writing the sample space as {HH, HT, TT} (3 outcomes), treating HT and TH as the same. Getting H first then T is a different path from T first then H.
  • Writing P(HH) = 12 + 12 = 1. Along a path the probabilities multiply (12 × 12), they do not add.
  • Drawing branches for the second toss from only one of the first-toss outcomes. Every first-toss outcome must branch again.

How this can come in the exam

MCQ (1 mark)

A fair coin is tossed twice. The probability of getting two tails is

  1. 14
  2. 13
  3. 12
  4. 34
Show answer

(A) 14
S = {HH, HT, TH, TT}; only TT is favourable: 14.

Short answer (2 marks)

A spinner with two equal sectors, Red and Blue, is spun twice. Draw a tree diagram, write the sample space, and find the probability of getting Blue both times.

Show answerFirst spin: R, B (12 each); from each, second spin R, B (12 each). S = {RR, RB, BR, BB}, 4 equally likely outcomes. P(BB) = 14.

Try one yourself

A fair coin is tossed twice. What is the probability that the second toss is heads?

Show answer

Favourable: HH, TH. P = 24 = 12.

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