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Slope and y-intercept · 5 marks

Draw the graph of the following equations, and identify their slopes and y-intercepts. Also, find the coordinates of the points where these lines cut the y-axis.

  1. (i) y = −3x + 4
  2. (ii) 2y = 4x + 7
  3. (iii) 5y = 6x − 10
  4. (iv) 3y = 6x − 11
  5. Parallel lines: Are any of the lines parallel?
Answer: (i) slope −3, y-intercept 4, (0, 4) (ii) slope 2, y-intercept 72, (0, 72) (iii) slope 65, y-intercept −2, (0, −2) (iv) slope 2, y-intercept −113, (0, −113). Lines (ii) and (iv) are parallel (both slope 2).

Step-by-step solution

Idea: Rewrite each equation as y = ax + b by dividing by the coefficient of y. Then a is the slope, b is the y-intercept, and the line cuts the y-axis at (0, b).

xy−4−3−2−1123−6−4−22460(i)(ii)(iii)(iv)

(i) y = −3x + 4

  1. Already in the form y = ax + b: slope −3, y-intercept 4, cuts the y-axis at (0, 4).½ mark
  2. Points to plot: (0, 4) and (1, 1). The line falls from left to right.½ mark
Slope −3, y-intercept 4, point (0, 4).

(ii) 2y = 4x + 7

  1. Divide by 2: y = 2x + 72. Slope 2, y-intercept 72 (3.5), cuts the y-axis at (0, 72).½ mark
  2. Points to plot: (0, 3.5) and (1, 5.5).½ mark
Slope 2, y-intercept 72, point (0, 72).

(iii) 5y = 6x − 10

  1. Divide by 5: y = 65x − 2. Slope 65, y-intercept −2, cuts the y-axis at (0, −2).½ mark
  2. Points to plot: (0, −2) and (5, 4).½ mark
Slope 65, y-intercept −2, point (0, −2).

(iv) 3y = 6x − 11

  1. Divide by 3: y = 2x − 113. Slope 2, y-intercept −113 (about −3.67), cuts the y-axis at (0, −113).½ mark
  2. Points to plot: (0, −113) and (4, 133), or (1, −53).½ mark
Slope 2, y-intercept −113, point (0, −113).

Parallel lines: Are any of the lines parallel?

  1. Lines with equal slopes are parallel. (ii) and (iv) both have slope 2 (and different y-intercepts), so lines (ii) and (iv) are parallel. No other pair has equal slopes (−3, 2, 65, 2).1 mark
Yes: 2y = 4x + 7 and 3y = 6x − 11 are parallel.
(i) slope −3, y-intercept 4, (0, 4); (ii) slope 2, y-intercept 72, (0, 72); (iii) slope 65, y-intercept −2, (0, −2); (iv) slope 2, y-intercept −113, (0, −113). Lines (ii) and (iv) are parallel.

Check: (iii): (5, 4) satisfies 5y = 6x − 10, since 20 = 30 − 10 ✓. (iv): (4, 133) gives 3 × 133 = 13 = 24 − 11 ✓.

Answer to write in the exam

(i)

y = −3x + 4

Slope = −3, y-intercept = 4

Points (0, 4), (1, 1); graph drawn

∴ Cuts the y-axis at (0, 4)

(ii)

y = 2x + 72

Slope = 2, y-intercept = 72

Points (0, 3.5), (1, 5.5); graph drawn

∴ Cuts the y-axis at (0, 72)

(iii)

y = 65x − 2

Slope = 65, y-intercept = −2

Points (0, −2), (5, 4); graph drawn

∴ Cuts the y-axis at (0, −2)

(iv)

y = 2x − 113

Slope = 2, y-intercept = −113

Points (0, −113), (1, −53); graph drawn

∴ Cuts the y-axis at (0, −113)

Parallel lines:

Slopes: −3, 2, 65, 2

(ii) and (iv): equal slopes 2, different y-intercepts

∴ Lines (ii) 2y = 4x + 7 and (iv) 3y = 6x − 11 are parallel

Common mistakes that cost marks

  • Reading the slope of 2y = 4x + 7 as 4. Divide by 2 first: the slope is 2.
  • Giving the y-intercept of (iii) as −10. After dividing by 5 it is −2.
  • Saying (ii) and (iv) are not parallel because the original equations look different. Compare slopes only after rewriting as y = ax + b.

How this can come in the exam

MCQ (1 mark)

The slope and y-intercept of 4y = 2x − 12 are

  1. 2 and −12
  2. 12 and −3
  3. 2 and −3
  4. 12 and −12
Show answer

(B) 12 and −3
y = 12x − 3.

Assertion–Reason (1 mark)

Assertion (A): The lines 3y = 9x + 2 and y = 3x − 5 are parallel.
Reason (R): Both lines cut the y-axis at the same point.

  1. Both A and R are true, and R is the correct explanation of A.
  2. Both A and R are true, but R is not the correct explanation of A.
  3. A is true but R is false.
  4. A is false but R is true.
Show answer

(C) A is true but R is false.
A is true: both slopes are 3. R is false: the y-intercepts are 23 and −5.

Try one yourself

Find the slope, the y-intercept and the point where 6y = −3x + 18 cuts the y-axis.

Show answer

y = −12x + 3: slope −12, y-intercept 3, point (0, 3).

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