Learnify Academy is a tuition centre in Bahrain. Classes are for students in Bahrain only.Tuition classes in Bahrain only

Symmetry of a circle · 2 marks

Draw a circle on the paper and cut along the circle. Fold the circular paper so that the boundaries overlap, then open it. You see a crease; it is a line of reflection symmetry of the circle. Does this line pass through the centre of the circle?

Answer: Yes. The crease always passes through the centre: it is a diameter. Every diameter of a circle is a line of reflection symmetry.

Step-by-step solution

Idea: When the boundaries overlap, every point P of the edge lands on another edge point P′, and the crease is the perpendicular bisector of PP′. The centre O is equidistant from P and P′ (both are radii), so O lies on that perpendicular bisector, which is the crease.

OPP′crease
  1. Take any point P on the edge. When the paper is folded with the boundaries overlapping, P lands on some point P′ of the edge.½ mark
  2. In a fold, the crease is the perpendicular bisector of the segment joining a point to the point it lands on. So the crease is the perpendicular bisector of PP′.½ mark
  3. The centre O is at the same distance from P and P′, since OP = OP′ = radius. Every point equidistant from P and P′ lies on the perpendicular bisector of PP′.½ mark
  4. So O lies on the crease. The crease is a line through the centre, so the part of it inside the circle is a diameter.½ mark
Yes. The crease passes through the centre, so it is a diameter. Every diameter is a line of reflection symmetry of the circle.

Check: Fold a second time in another direction: the two creases cross at one point, and a ruler shows this point is the same distance from every point of the edge.

Answer to write in the exam

On folding, point P of the edge falls on point P′ of the edge.

Crease = perpendicular bisector of PP′ (property of a fold)

OP = OP′ (radii) ⇒ O lies on the perpendicular bisector of PP′

∴ Yes; the crease passes through the centre O, i.e. it is a diameter.

Common mistakes that cost marks

  • Saying “yes, because it looks like it”. The reason is that the centre is equidistant from P and its folded image P′, so it lies on the perpendicular bisector of PP′, which is the crease.
  • Thinking any chord is a line of symmetry. Only chords through the centre (diameters) are.
  • Confusing a line of reflection symmetry with rotational symmetry. Folding tests reflection; turning tests rotation.

How this can come in the exam

MCQ (1 mark)

How many lines of reflection symmetry does a circle have?

  1. 1
  2. 2
  3. 4
  4. Infinitely many
Show answer

(D) Infinitely many
Every diameter is a line of reflection symmetry, and a circle has infinitely many diameters.

Assertion–Reason (1 mark)

Assertion (A): Every line of reflection symmetry of a circle passes through its centre.
Reason (R): The centre of a circle is equidistant from every point on the circle.

  1. Both A and R are true, and R is the correct explanation of A.
  2. Both A and R are true, but R is not the correct explanation of A.
  3. A is true, but R is false.
  4. A is false, but R is true.
Show answer

(A) Both A and R are true, and R is the correct explanation of A.
Both are true. A line of symmetry is the perpendicular bisector of PP′ for each edge point P and its image P′; since the centre is equidistant from P and P′ (R), it lies on that line. So R explains A.

Try one yourself

Is a chord that does not pass through the centre a line of symmetry of the circle? Give a reason.

Show answer

No. If we fold along such a chord, the smaller piece of the circle does not cover the larger piece, so the boundaries do not overlap. Only diameters are lines of symmetry.

More questions like this

All Circles questions · All maths questions