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Number of solutions of a pair · 3 marks

Does a pair of linear equations always have a unique solution? Can you analyse this using the Elimination Method? While subtracting the equations to eliminate a particular variable, if the other variable remains, then clearly there is a unique solution. But what if the second variable gets eliminated too while eliminating the first variable? Can you think of a situation where this happens?

Answer: No. If one equation’s x– and y-coefficients are the same multiple of the other’s (e.g. x − y = 10 and 10x − 10y = 100), eliminating x removes y too. Then we get either 0 = 0 (infinitely many solutions) or something false like 0 = 1 (no solution).

Step-by-step solution

Idea: Elimination subtracts matched equations. Both variables vanish together exactly when the coefficients of x and y are in the same ratio; what is left is a statement about the constants only.

  1. Both variables disappear together when, after matching the x-coefficients, the y-coefficients also match, i.e. when a1a2 = b1b2.1 mark
  2. Case 1: x − y = 10 and 10x − 10y = 100. Multiply the first by 10: 10x − 10y = 100. Subtract: 0 = 0. Always true, so every solution of x − y = 10 works: infinitely many solutions.1 mark
  3. Case 2: x − y = 10 and 10x − 10y = 101. Multiply the first by 10 and subtract: 0 = 1. Impossible, so no solution.½ mark
  4. So a pair does not always have a unique solution: it can have one, infinitely many, or none.½ mark
No. When the x- and y-coefficients are proportional, both variables are eliminated together, leaving 0 = 0 (infinitely many solutions) or a false statement such as 0 = 1 (no solution).

Check: In case 1, (12, 2) and (0, −10) both satisfy both equations ✓. In case 2, 10x − 10y cannot be both 100 and 101 ✓.

Answer to write in the exam

Both variables vanish when a1a2 = b1b2

e.g. x − y = 10, 10x − 10y = 100: 10 × (1) − (2) ⇒ 0 = 0 ⇒ infinitely many solutions

e.g. x − y = 10, 10x − 10y = 101: ⇒ 0 = 1 ⇒ no solution

∴ A pair need not have a unique solution

Common mistakes that cost marks

  • Reading 0 = 0 as “the solution is x = 0, y = 0″. It means the equations are the same, with infinitely many solutions.
  • Thinking 0 = 1 means a calculation error. If the working is right, it shows there is no solution.

How this can come in the exam

MCQ (1 mark)

Eliminating x from 2x + 3y = 5 and 4x + 6y = 9 leads to

  1. a unique solution
  2. 0 = 0
  3. 0 = 1
  4. y = 1
Show answer

(C) 0 = 1
2 × (1): 4x + 6y = 10; subtract (2): 0 = 1, so no solution.

Try one yourself

What happens when you eliminate x from 3x − y = 2 and 6x − 2y = 4?

Show answer

2 × (1) − (2) gives 0 = 0: infinitely many solutions (same line).

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