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Explicit and recursive rules · 4 marks

Consider the sequence that is generated by the explicit formula sn = 5n − 2.

  1. (a) Can you write the first 6 terms of this sequence?
  2. (b) What is the 100th term? The 1000th term?
  3. (c) Let us check if the numbers 308 and 473 are terms of this sequence.
  4. (d) Can you explain why we need n to be a natural number?
Answer: First 6 terms: 3, 8, 13, 18, 23, 28. 100th term = 498; 1000th term = 4998. 308 is the 62nd term. 471 is not a term (n = 94.6); 473 is the 95th term. n must be a natural number because it counts a position.

Step-by-step solution

Idea: To find a term, substitute n. To test a number, set 5n − 2 equal to it and solve: the number is a term only if n comes out as a natural number.

(a) Can you write the first 6 terms of this sequence?

  1. s1 = 5 × 1 − 2 = 3, s2 = 5 × 2 − 2 = 8, s3 = 13.½ mark
  2. s4 = 18, s5 = 23, s6 = 28. (Each term is 5 more than the one before.)½ mark
3, 8, 13, 18, 23, 28

(b) What is the 100th term? The 1000th term?

  1. s100 = 5 × 100 − 2 = 500 − 2 = 498.½ mark
  2. s1000 = 5 × 1000 − 2 = 5000 − 2 = 4998.½ mark
498 and 4998

(c) Let us check if the numbers 308 and 473 are terms of this sequence.

  1. 308: 5n − 2 = 308 ⇒ 5n = 310 ⇒ n = 62. This is a natural number, so 308 is the 62nd term.½ mark
  2. The worked solution then tests 471: 5n − 2 = 471 ⇒ 5n = 473 ⇒ n = 94.6. This is not a natural number, so 471 is not a term.½ mark
  3. The number printed in the question is 473, so check it too: 5n − 2 = 473 ⇒ 5n = 475 ⇒ n = 95. So 473 is the 95th term. (The question and its working use different numbers; both are answered here.)½ mark
308 is the 62nd term; 471 is not a term; 473 is the 95th term

(d) Can you explain why we need n to be a natural number?

  1. n is a position: 1st, 2nd, 3rd, … There is no ‘94.6th’ term, and no 0th or negative position, so a number is a term only when n is 1, 2, 3, …½ mark
Because n counts the position of a term, and positions are 1, 2, 3, …
First six terms 3, 8, 13, 18, 23, 28; s₁₀₀ = 498 and s₁₀₀₀ = 4998; 308 is the 62nd term; 471 is not a term (n = 94.6); 473 is the 95th term; n must be a natural number because it is a position.

Check: 5 × 62 − 2 = 308 ✓; 5 × 95 − 2 = 473 ✓. Every term ends in 3 or 8, and 471 ends in 1, so it cannot be a term ✓.

Answer to write in the exam

(a)

sn = 5n − 2

s1 = 3, s2 = 8, s3 = 13, s4 = 18, s5 = 23, s6 = 28

∴ 3, 8, 13, 18, 23, 28

(b)

s100 = 5 × 100 − 2 = 498

s1000 = 5 × 1000 − 2 = 4998

(c)

5n − 2 = 308 ⇒ 5n = 310 ⇒ n = 62

∴ 308 is the 62nd term.

5n − 2 = 471 ⇒ 5n = 473 ⇒ n = 94.6 (not a natural number)

∴ 471 is not a term.

5n − 2 = 473 ⇒ 5n = 475 ⇒ n = 95

∴ 473 is the 95th term.

(d)

n is the position of a term: 1st, 2nd, 3rd, …

∴ n must be a natural number.

Common mistakes that cost marks

  • Stopping at n = 94.6 and saying ‘471 is the 94.6th term’. A decimal answer means the number is not a term.
  • Solving 5n − 2 = 308 as 5n = 306. Move −2 across as +2: 5n = 310.
  • Giving the value of n (62) as ‘the term’. 62 is the position; 308 is the term.

How this can come in the exam

MCQ (1 mark)

Which of these is a term of the sequence sn = 5n − 2?

  1. 250
  2. 253
  3. 255
  4. 257
Show answer

(B) 253
5n − 2 = 253 gives 5n = 255, n = 51, a natural number. The others give n = 50.4, 51.4, 51.8.

Short answer (2 marks)

Is 600 a term of the sequence sn = 7n + 4? Give a reason.

Show answer7n + 4 = 600 ⇒ 7n = 596 ⇒ n = 85.14… (1 mark). This is not a natural number, so 600 is not a term (1 mark).

Try one yourself

For sn = 6n − 1, write the first four terms and decide whether 155 and 160 are terms.

Show answer

5, 11, 17, 23. 6n − 1 = 155 gives n = 26, so 155 is the 26th term. 6n − 1 = 160 gives n = 26.83…, so 160 is not a term.

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