Algebra tiles can be used to represent products and find factors.
1. Figure out the product of x + 2 and x + 3 using algebra tiles.
2. Lay out algebra tiles for x2 + 11x + 30 in such a way that you will see its factors.
- 1. Figure out the product of x + 2 and x + 3 using algebra tiles.
- 2. Lay out algebra tiles for x2 + 11x + 30 in such a way that you will see its factors.
Step-by-step solution
Idea: A rectangle made of tiles has area = length × breadth. The x2-tile is an x × x square, an x-tile is x × 1, and a unit tile is 1 × 1. Building a rectangle with sides (x + p) and (x + q) always uses one x2-tile, p + q x-tiles and p × q unit tiles.
1. Figure out the product of x + 2 and x + 3 using algebra tiles.
- Make a rectangle with top side x + 2 (an x length and 2 units) and left side x + 3 (an x length and 3 units).½ mark
- Fill it: the x × x corner is one x2-tile; the 2-unit strip beside it holds 2 x-tiles; the 3-unit strip below it holds 3 x-tiles; the 2 × 3 corner holds 6 unit tiles (see the left diagram).½ mark
- Count: 1 x2-tile, 2 + 3 = 5 x-tiles, 6 unit tiles.½ mark
- So (x + 2)(x + 3) = x2 + 5x + 6. Check with distributivity: x2 + 3x + 2x + 6 = x2 + 5x + 6 ✓.½ mark
2. Lay out algebra tiles for x2 + 11x + 30 in such a way that you will see its factors.
- Tiles: one x2-tile, 11 x-tiles, 30 unit tiles. The 11 x-tiles must be split into p beside and q below, with p + q = 11 and the corner p × q = 30.½ mark
- Try pairs adding to 11: 1 × 10 = 10, 2 × 9 = 18, 3 × 8 = 24, 4 × 7 = 28, 5 × 6 = 30 ✓.½ mark
- Place 5 x-tiles beside the x2-tile and 6 below it, and fill the corner with the 30 unit tiles in 5 columns and 6 rows (right diagram). Every tile is used and the shape is a rectangle.½ mark
- Its sides are x + 5 and x + 6, so x2 + 11x + 30 = (x + 5)(x + 6).½ mark
Check: Put x = 10: (12)(13) = 156 = 100 + 50 + 6 ✓; (15)(16) = 240 = 100 + 110 + 30 ✓.
Answer to write in the exam
1.
Tiles: one x2 tile, 2 + 3 = 5 x tiles, 2 × 3 = 6 unit tiles
(x + 2)(x + 3) = x2 + 3x + 2x + 6
∴ (x + 2)(x + 3) = x2 + 5x + 6
2.
11x = 5x + 6x, since 5 + 6 = 11 and 5 × 6 = 30
Tiles: one x2 tile, 5 x tiles beside it, 6 x tiles below it, 30 unit tiles in a 5 × 6 block
Sides of the rectangle: (x + 5) and (x + 6)
∴ x2 + 11x + 30 = (x + 5)(x + 6)
Common mistakes that cost marks
- Counting the x-tiles as 2 × 3 = 6 instead of 2 + 3 = 5. The x-tiles add; it is the unit tiles that multiply.
- Putting all 11 x-tiles along one side. Then the corner is 0 units wide and the 30 unit tiles cannot fit; split them 5 beside and 6 below.
- Choosing a pair with product 30 but the wrong sum, such as 3 and 10 (sum 13) or 2 and 15 (sum 17).
How this can come in the exam
A rectangle made of algebra tiles uses one x2-tile, 7 x-tiles and 10 unit tiles. Its sides are
- x + 1 and x + 10
- x + 2 and x + 5
- x + 3 and x + 4
- x + 7 and x + 10
Show answer
(B) x + 2 and x + 5
Need sum 7 and product 10: 2 and 5. (x + 2)(x + 5) = x2 + 7x + 10.
Assertion (A): The tiles for (x + 2)(x + 3) include 6 unit tiles.
Reason (R): The unit tiles fill a corner that is 2 units by 3 units.
- Both A and R are true, and R is the correct explanation of A.
- Both A and R are true, but R is not the correct explanation of A.
- A is true but R is false.
- A is false but R is true.
Show answer
(A) Both A and R are true, and R is the correct explanation of A.
2 × 3 = 6, so R explains A.
Try one yourself
Factorise x2 + 10x + 24 by thinking about algebra tiles.
Show answer
Need sum 10, product 24: 4 and 6. The rectangle is (x + 4) by (x + 6), so x2 + 10x + 24 = (x + 4)(x + 6).
More questions like this
- We have seen that (x + 3)(x + 4) = x2 + 7x + 12.
Also (x + 6)(x + 7) = x2 + 13x + 42.
Generalise the pattern to get an expression for (x + a) (x + b). - Now consider the case where we have a rectangle of sidelengths 2x + 3 and 3x + 1, as shown in the figure. What can you say about its area (2x + 3) (3x + 1)?
- Fill in the blanks with the appropriate expressions to make the equation true.
(px + a) (qx + b) = (_____)x2 + (_____)x + _____ .
Also, verify your answer using the distributive property. - Let us begin with x2 + 7x + 12 = x2 + (a + b)x + ab.
- Let us try to factor x2 + 11x + 30 in a similar manner.